Very interesting question!
Let's try to get something that would work for just 5 for now.
Any of these numbers would leave a remainder of 1 when divided by just 5:
6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61, 66, 71, 76, 81, 86, ...
Notice that they all look like 5*(something) + 1. Basically, they are all multiples of 5 plus 1.
Let's see what would work for just 8:
9, 17, 25, 33, 41, 49, 57, 65, 73, 81, 89, ...
Are there any matches... AHA! It's 81. This is the lowest positive integer greater than 1 that follows the rule for both 5 and 8.
Hey there!
“4y + 3x”
If x = 5 and y = -3, then substitute it into the equation
4(-3) + 3(5)
4(-3) = -12
-12 + 3(5)
3(5) = 15
-12 + 15
= 3
Answer: 3
Good luck on your assignment and enjoy your day!
~Amphitrite140:)
Y = -3/2x + 4
I need 20 characters so hi
16x + 21y = 555
Step-by-step explanation:
Let x be the no. of 18-hole course
And y be the no. of golf balls
16x + 21y = 555
