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asambeis [7]
1 year ago
13

There are 150 people ina golf club.a) there are 50%more men than women in the golf club. How many mena nd how many women are the

r in the golf club.
Mathematics
1 answer:
lana66690 [7]1 year ago
5 0

The percentage computed shows that the number of women is 60 while men are 90.

<h3>How to calculate percentage?</h3>

Let the number of women be represented by x.

Since there are are 50% more men than women in the golf club, the number of men will be:

= x + (50% × c)

= x + 0.5x

= 1.5x

Therefore, 1.5x + x = 150

2.5x = 150

x = 150/2.5

x = 60

Number of women = 60

Number of men = 1.5x = 1.5 × 60 = 90

Learn more about percentages on:

brainly.com/question/24304697

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What is (2.3x10^-3)/(4.6x10^-7) written in scientific notation? Please show how you solved this.
lions [1.4K]
(2.3*10^-3) / (4.6*10^-7)

(2.3*0.001) / (4.6*0.0000001)  *10^-3=0.001 & 10^-7=0.0000001*

(0.0023) / (0.00000046)   *2.3*0.001=0.0023 & 4.6*0.0000001=0.00000046*

5000  *0.0023/0.00000046*

So the answer is 5000
5 0
3 years ago
Is the answer right?
son4ous [18]
Almost. Where you put -(-5) and then later on you say it’s -5. It’s not. It would be +5 or just 5 because - and - makes a plus :)
7 0
2 years ago
Two random variables x and y are independent if the value of x does not affect the value of y. If the variables are not​ indepen
jeyben [28]

Answer: \mu_{x+y} = 3026

              \mu_{x-y}= 30

Step-by-step explanation: Average sum of the female and male's test score is the sum of expected value of each gender:

\mu_{x+y}=\mu_{x}+\mu_{y}

Assuming x represents the random male selected and y represents the random female selected:

\mu_{x+y}=1528+1498

\mu_{x+y}= 3026

The average sum of their scores is 3026.

Average difference is the difference between the expected value (mean) of each gender:

\mu_{x-y}=\mu_{x}-\mu_{y}

\mu_{x-y}= 1528 - 1498

\mu_{x-y}= 30

The average difference of their scores is 30.

6 0
2 years ago
Select the correct answer from each drop-down menu.
ruslelena [56]

The independent variable in the relationship is the <u><em>Number of Months</em></u> and should be placed on the<em> </em><u><em>x-axis</em></u>

The dependent variable in the relationship is the <em><u>Number of Fish</u></em> and should be placed on the <u><em>y-axis</em></u>

Step-by-step explanation:

Let us explain the independent and dependent variables of a relation

  • The independent variable is the input of the relation
  • The dependent variable is the output of the relation
  • The values of dependent variables depend on the values of independent variables
  • When the relation represented graphically the independent variable placed on the x-axis and the dependent variable placed on the y-axis

The table:

→ Number of Months:  0       :  1         :  2       :  3          :  4

→ Number of Fish      : 1,024 :  1,280 :  1600 :  2,000  :  2,500

Let us check is their any constant ratio between the consecutive values of the number of fish

∵ 1,280 ÷ 1,024 = 1.25

∵ 1,600 ÷ 1.280 = 1.25

∵ 2,000 ÷ 1,600 = 1.25

∵ 2,500 ÷ 2,000 = 1.25

∴ The table represent an exponential function, where the input

   is the number of months and the output is the number of fish

∵ The input is independent variable

∴ The independent variable is the number of months

∵ The output is the dependent variable

∴ The dependent variable is the number of fish

∵ The independent variable is placed on the x-axis

∴ The number of months should be place on the x-axis

∵ The dependent variable is placed on the y-axis

∴ The number of fish should be place on the y-axis

The independent variable in the relationship is the <u><em>Number of Months</em></u> and should be placed on the<em> </em><u><em>x-axis</em></u>

The dependent variable in the relationship is the <em><u>Number of Fish</u></em> and should be placed on the <u><em>y-axis</em></u>

<u><em /></u>

Learn more:

You can learn more about the relation in brainly.com/question/10708697

#LearnwithBrainly

6 0
3 years ago
PLEASE NO LINKS OR SITES!!!! JUST ANSWERS. THANK YOU!
ladessa [460]

Answer:

7 pizzas, EDGE 2020? Lol

5 0
2 years ago
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