Sin51=y/12
y=12sin51 units
y≈9.33 units (to nearest hundredth of a unit)
...
tanα=12/5
α=arctan2.4°
α≈67.38° (to nearest hundredth of a degree)
...
tan13=x/24
x=24tan13 units
x≈5.54 units (to nearest hundredth of a unit)
...
sin20=10/x
x=10/sin20 units
x≈29.24 units (to nearest hundredth of a unit)
Answer:
63 students.
Step-by-step explanation:
x students.
34 have science 28 have math 5 math and science 6 neither.
6 neither means there were at least 6 students so our number goes up to 6 students.
34 have science 28 have math 5 have both.
34-5 and 28-5
29 and 23
29+23 is 52 +5 is 57 +6 is 63.
63 students.
HOpe this helps!
Merry Christmas!
<span><span>The </span>President of India<span> is
the formal </span>Head of State,
head of the executive and legislature of India and is the commander-in-chief of the Indian Armed Forces. Pranab Kumar Mukherjee<span> born on December 11, 1935
is the 13th and current </span>President of India, in
office since July 2012.</span>
Answer:
Hence the correct answer is option (A) 4.708.
Step-by-step explanation:
Solution:-
Now, we need to find the angle of the sector by using sector formula,
We now convert the angle to radian
Now we calculate the length of arc by arc formula
So, The length of steel that must be replaced is 4.708 ft.
Answer:
it will turn out to be a repeating decimal so put a little line over the first 3 to the right of the decimal (517.8333333333)
Step-by-step explanation:
