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Svetllana [295]
3 years ago
7

Find the distance between the parallel lines

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

The distance between the parallel lines is 0.92

Step-by-step explanation:

Given the two parallel lines:

<h2>4x - 6y + 20 + 0</h2><h2>6x - 9y + 20 = 0 </h2>

To find the distance between the two parallel lines:

  • First, we get a point on one of the lines, as follows:
<h2>4x - 6y + 20 = 0</h2><h2>4 (4) + 20 = 6y</h2><h2>36 = 6y</h2><h2>y = 6</h2><h2>(4, 6)</h2>
  • Once we have a point on a line, we calculate the distance from that point to the other line using the formula for the distance from a point to a line:

<u>See In Photo</u>

Where:

A = 6

B = -9

C = 20

px = 4

py = 6

Then:

<u>See in 2nd Photo</u>

<u />

Answer:

the distance between the parallel lines is 0.92

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Find the value of in the triangle shown below<br><br> 9, 7, and x around the triangle
enot [183]

Answer:

5.66 units

Step-by-step explanation:

A's per our discussion, x is a leg of right triangle.

Therefore, by Pythagoras theorem:

x =  \sqrt{ {9}^{2}  -  {7}^{2} }  \\  =  \sqrt{81 - 49}  \\  =  \sqrt{32}

x =  \sqrt{ {16}^{2}  -  {12}^{2} }  \\  =  \sqrt{256 - 144}  \\  =  \sqrt{112}

4 0
3 years ago
Denise spent $3.45 on snacks every day for 11 days. What is the amount of money Denise spent
musickatia [10]

Answer:

37.95

Step-by-step explanation:

Because 3.45 x 11 is 37.95.

5 0
3 years ago
Read 2 more answers
Square root 1.96? is rational irrational
Kruka [31]

Answer:

Rational

Step-by-step explanation:

An irrational number is a number with forever continuing decimals. Plug it into the calc and you can see if there is a long decimal line that ends. You should get 1.4 in the calc, and since it does end, it is a rational number.

4 0
3 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
I just need numbers 23 and 24
kobusy [5.1K]
23; 20+4+9+ 28
he can estimate by rounding the numbers
24;19.99+4.19+8.50+27.75=
24.18+ 8.25+28=
24.18+36.25=
$60.43
7 0
3 years ago
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