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Svetllana [295]
3 years ago
7

Find the distance between the parallel lines

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

The distance between the parallel lines is 0.92

Step-by-step explanation:

Given the two parallel lines:

<h2>4x - 6y + 20 + 0</h2><h2>6x - 9y + 20 = 0 </h2>

To find the distance between the two parallel lines:

  • First, we get a point on one of the lines, as follows:
<h2>4x - 6y + 20 = 0</h2><h2>4 (4) + 20 = 6y</h2><h2>36 = 6y</h2><h2>y = 6</h2><h2>(4, 6)</h2>
  • Once we have a point on a line, we calculate the distance from that point to the other line using the formula for the distance from a point to a line:

<u>See In Photo</u>

Where:

A = 6

B = -9

C = 20

px = 4

py = 6

Then:

<u>See in 2nd Photo</u>

<u />

Answer:

the distance between the parallel lines is 0.92

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Determine whether the three points are the vertices of a right triangle. (6, -6), (9, -6), (9, 1)
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Answer:

The three given points are the vertices of a right triangle.

Step-by-step explanation:

To determine that the three points are the vertices of a right triangle let us find the distance between each two points

The formula of the distance is d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }

∵ x_{1} = 6 and y_{1} = -6

∵ x_{2} = 9 and y_{2} = -6

∴ d_{1} = \sqrt{(9-6)^{2}+(-6--6)^{2}}=\sqrt{9+0}

∴ d_{1} = 3

∵ x_{1} = 6 and y_{1} = -6

∵ x_{2} = 9 and y_{2} = 1

∴ d_{2} = \sqrt{(9-6)^{2}+(1--6)^{2}}=\sqrt{9+49}

∴ d_{2} = \sqrt{58}

∵ x_{1} = 9 and y_{1} = 1

∵ x_{2} = 9 and y_{2} = -6

∴ d_{3} = \sqrt{(9-9)^{2}+(-6-1)^{2}}=\sqrt{0+49}

∴ d_{3} = 7

<em>Let us use the fact that if the square of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle at the vertex which opposite to the longest side</em>

∵ The longest side is \sqrt{58}

∵ The other two sides are 3 and 7

∵ ( \sqrt{58} )² = 58

∵ (3)² + (7)² = 9 + 49 = 58

∴  ( \sqrt{58} )² = (3)² + (7)²

- By using the fact above

∴ The triangle is a right triangle

The three given points are the vertices of a right triangle.

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4 years ago
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3 0
2 years ago
Pls help me with this!!!
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Step-by-step explanation:

I'm not sure what you need help with, since what you have written down is correct. However, if you are looking for an explanation, here it is:

x + 5 < -2

To solve for x, we have to get x on one side by itself. Whatever you do to one side, you have to do to the other. Let's get rid of 5 to get x by itself.

x + 5 < -2    (Subtract 5 from both sides)

x < -7

Perfect! Basically what this is saying, is that all the values x can equal have to be less than -7. The sign < means less than.

For the signs < (less than) and > (greater than), we use an open circle.

For the signs ≤ (less than or equal to) and ≥ (greater than or equal to), we use a closed circle.

This is why we use an open circle for this example since x is LESS THAN -7.

The arrow is pointing to the left because these numbers are less than -7.

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2 years ago
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