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Zigmanuir [339]
2 years ago
9

What is the perimeter of the triangle? units

Mathematics
1 answer:
never [62]2 years ago
8 0

Answer:

36 units

Step-by-step explanation:

Break it into 2 right triangles with legs  6 and 8    then the hypot = 10

8 +8 + 10 + 10 =36

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hi:) for 5(b) , I got 157.7 & 22.3 but in the answer key, the only correct answer is 157.7. I thought there should be 2 poss
n200080 [17]

Answer:

Θ = 157.7°

Step-by-step explanation:

Given

cosΘ = - 0.925

Since cosΘ < 0 then Θ is in the second or third quadrant.

Since 0° ≤ Θ ≤ 180° then Θ is in the second quadrant. thus

Θ = cos^{-1}(- 0.925) = 157.7° ← angle in second quadrant

8 0
3 years ago
Read 2 more answers
-4+(-10t)/0.5+15
ziro4ka [17]
The answer is C because when you divide it out you get 6
6 0
3 years ago
You collect 140 total pieces of candy trick or treating and 35 of them are m&amp;m's. What fraction of the candy is not m&amp;m'
tekilochka [14]

\frac{3}{4} of the candy is not m&m's.

Step-by-step explanation:

Given,

Total pieces of candy = 140

Number of m&m's = 35

Fraction = \frac{Number\ of\ m&m}{Total\ pieces\ of\ candy}

Fraction = \frac{35}{140}

Both 35 and 140 are multiples of 7, therefore,

Fraction of m&m's = \frac{5}{20} = \frac{1}{4}

As the number of m&m's fraction and not m&m's fraction will make a total of 1, therefore

fraction of m&m's + fraction of not m&m's = 1

fraction of not m&m's = 1 - fraction of m&m's

fraction of not m&m's = 1-\frac{1}{4}=\frac{4-1}{4}

fraction of not m&m's = \frac{3}{4}

\frac{3}{4} of the candy is not m&m's.

Keywords: fraction, subtraction

Learn more about fractions at:

  • brainly.com/question/8929610
  • brainly.com/question/8908016

#LearnwithBrainly

7 0
3 years ago
Estimate the MAXIMUM number of people that can be in your park at one time, before it’s too crowded. Use this information for yo
Serga [27]
75,000 divided by 150, is 500, meaning they allow 500 people per acre. 500 times 145 is 72,500, meaning the capacity for a park your size should be 72,500 people.
3 0
3 years ago
A bowl contained 250 skittles. The result of 25 fruit-flavored candies pulled at random is given below. Based on this informatio
Anastaziya [24]

OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!

7 0
3 years ago
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