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Temka [501]
2 years ago
8

How many integers from 1 to 100 have a factor of 3?

Mathematics
1 answer:
alekssr [168]2 years ago
7 0

Answer: 33 integers

Step-by-step explanation:

The numbers with a factor of 3 must be a multiple of 3. Therefore, since 99 is the greatest multiple of 3 that is less than 100, we can <u>divide 99 by 3</u> to get <u>33 integers</u> (for every 3 consecutive integers, there is one multiple of 3). We can also divide 100 by 3 to get 33 1/3, which rounds to 33 integers.

I hope this helps!

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Answer: f(x) · g(x)=-32x³+104x²-100x+100

Step-by-step explanation:

Since we are given f(x) and g(x), all we have to do is multiply them together.

f(x) · g(x)=(4x-10)(-8x²+6x-10)                              [distribute by FOIL]

f(x) · g(x)=-32x³+24x²-40x+80x²-60x+100         [combine like terms]

f(x) · g(x)=-32x³+104x²-100x+100

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3 years ago
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ruslelena [56]

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8 0
3 years ago
. Anna was thinking of a number. She told Bill that if he squared her number followed by subtracting 11 times her, and adding 4,
Snowcat [4.5K]

Answer:

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Step-by-step explanation:

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This implies that:

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3 years ago
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Step-by-step explanation:

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