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olga55 [171]
4 years ago
5

You have a coord grid that is 96x96. what is the minimum number of bits that you will need to encode a coordinate in that space

Mathematics
1 answer:
Alinara [238K]4 years ago
7 0
One bit can code 2 type of possibilities. That mean 1 bit code 2^1 possibilities, 2 bits code 2^2 possibilities and X amount of bits will code 2^X possibilities. In this case, you need to code 96x96 possibilities= 9216 possibilities. To answer this question, you need to find out how much it will be in 2^X form.  The fast way  to solve it by dividing it with 32(2^5) until the value <32 then divide it with 2(2^1) till it become <1

9216/32= 288
288/32= 9 -->take the 1 extra to made it 8
8/2= 4
4/2= 2
2/2=1
1/2= 0.5

The number is divided by 32 two times and divided by 2 four times. Then the number of bits would be
5*2 + 1*4= 14 bits
The answer will be 14 bits since 14 bits will code 16384 possibilities
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6 0
4 years ago
Expand and simplify (x+5)(x+2)
Savatey [412]
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F:First
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So, given the expression (x+5)(x+2), lets multiply the first two terms.

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now the outer two terms

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now the inner terms

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and the last terms...

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When we combine these expressions we get:

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5 0
3 years ago
Please please help!
Dimas [21]

Answer:

C

Step-by-step explanation:

Calculate the distance (d) using the distance formula

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8 0
3 years ago
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xeze [42]

Answer:

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=> x=(160x100)/80

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Thus, 200 people surveyed.

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4 0
4 years ago
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lukranit [14]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
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