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Nataly_w [17]
2 years ago
6

Given that a/b = 3/5 and b/c = 4/5 Find a:b:c

Mathematics
1 answer:
Taya2010 [7]2 years ago
6 0

Answer:

12:20:25

I thnk this is it. I'm not sure though

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PLEASE HELP ILL MARK YOU BRAINLIEST!!!!! 75 POINTS Use the function f(x) = 2x2 − 5x + 3 to answer the questions. Part A: Complet
andrew-mc [135]

Answer:

A. (2x-3)(x-1)

B. (1,0) \\(1.5,0)

2x^2-5x+3\\\frac{5(+ or -)\sqrt{(-5)^2-(4)(2)(3)}  }{2(2)} \\\frac{5(+ or -)\sqrt{25-24}  }{4}\\\frac{5(+ or -)\sqrt{1}  }{4}\\ \frac{5(+ or -)1  }{4}\\\frac{5+1}{4} or \frac{5-1}{4} \\ \frac{6}{4} =1.5  and \frac{4}{4} =1

C. Both sides will continue to increase as they go because this is an even degree quadratic equation.

D. You use the two x-intercepts to make sure it is in the correct area and since we know the end behavior all you'd have to assume is that it continues to go up so any negative answers you may accidentally receive would be incorrect.

3 0
3 years ago
(p^2 )^5<br> find the product
kvv77 [185]

Answer:

p^10

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4 0
3 years ago
Read 2 more answers
the sum of the first three terms of a sequence Is 42 The fourth term is 24. find u1 and the common difference
e-lub [12.9K]

10=2d

Given:

The sum of the first three terms of a sequence Is 42.

The fourth term is 24.

To find:

The  u₁ and the common difference

Step-by-step explanation:

nth term of a sequence is

u_n=u_1+(n-1)d

where, u₁ is first term and d is common difference.

4th term is 24.

u_4=u_1+(4-1)d

24=u_1+3d           ...(i)

Sum of nth term of an AP is

S_n=\dfrac{n}{2}[2u_1+(n-1)d]

Sum of first three terms is 42.

S_3=\dfrac{3}{2}[2u_1+(3-1)d]

42=\dfrac{3}{2}[2u_1+2d]

Divide both sides by 3.

14=u_1+d          ...(ii)

On subtract (ii) from (i), we get

10=2d

5=d

Put d=5 in equation (ii).

14=u_1+5

14-5=u_1

9=u_1

Therefore, the first term is u_1=9 and common difference is d=5 .

6 0
3 years ago
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