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Rasek [7]
2 years ago
11

Please help me with question 36. I don’t know the answer

Mathematics
1 answer:
Eva8 [605]2 years ago
4 0

Answer:

Period = \frac{\pi }{4}

Amplitude = 4

Step-by-step explanation:

To find the answer, use the form <em>a</em>cos(<em>b</em>x - <em>c</em>) + <em>d:</em>

a = -4

b = 8

c = 0

d = 0

The amplitude is the absolute value of <em>a</em>, so:

|<em>a</em>| = |-4| = 4

To find the period, use this equation:

\frac{2\pi }{b}

Replace <em>b</em> with 8 in the formula and solve:

\frac{2\pi }{8} = \frac{\pi }{4}                Simplify

So, the period is equal to \frac{\pi }{4}

Hope this helps!!

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Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

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Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

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