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marin [14]
3 years ago
6

Find the missing side length assuming lines that appear to be tangent are tangent. Show work on piece of paper.

Mathematics
1 answer:
KIM [24]3 years ago
3 0

Answer:

20

Step-by-step explanation:

Since the line of length 16 is a tangent to the circle, then the angle between it and the radius is right.

? is the hypotenuse of the right triangle formed.

Using Pythagoras' identity on the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

?² = 12² + 16² = 144 + 256 = 400 ( take the square root of both sides )

? = \sqrt{400} = 20

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On a given planet, the weight of an object varies directly with the mass of the object. Suppose that an object whose mass is 9 k
nadya68 [22]

Answer:

6 kg

Step-by-step explanation:

Given is weight of an object directly varies with the mass of the object .

Let the constant of proportionality be k

So,

Weight = K×(mass of the object)

For an object , weight = 45 N

                        mass = 9 kg

So , 45 = K×9

      K = 5.

Now, for the other object ,

Weight = 30 N. K = 5 (as obtained above)

So, 30 = 5×(mass of the object)

mass of the object = 6 kg.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=8%20%2B%203%20%5Ctimes%204" id="TexFormula1" title="8 + 3 \times 4" alt="8 + 3 \times 4" align
Ira Lisetskai [31]

Answer:

20 is correct answer

Step-by-step explanation:

8+3×4

=8+12

=20

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8 0
3 years ago
Read 2 more answers
ANSWER ASAPPP PLSSS. ILL MARK BRAINLIEST TOO
nevsk [136]

Answer:

Step-by-step explanation:

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

f(1) = 10(1.02)^1

f(1) = 10(1.02)

f(1) = 10.2

(1, 10.2)

f(5) = 10(1.02)^5

f(5) = 10(1.1040808)

f(5) = 11.040808

f(1)=10(1.02)^1

f(1)=10.2

Average rate= (fn2-fn1)/(n2-n1)

                     =11.04-10.2/(5-1)

                    =0.22

the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.  

3 0
3 years ago
Read 2 more answers
madeline studies honeybees. every week she weighs the same honeybee hive, the first week the hive weighs 11.607 kilograms. its w
fomenos
So, we already know that one hive has a weight of 11.607kg and .204kg is add each week, so we add on .204kg times, w, representing weeks onto 11.607kg and our t is our total of weight of a hive with respect to weeks

w = weeks \\ t = total \: weight \: with \: respect \: to \: weeks
So in this case our w is 7.5 weeks and now we evaluate t

w = 7.5 \: weeks \\ t = ?
Solve
11.607kg + .204kg(w) = t \\ 11.607kg + .204kg(7.5) = t \\ t = 13.137kg
Answer:

Hive's weight will increase by 1.53kg in 7.5 weeks to 13.137kg
6 0
3 years ago
Using six random samples, the average number of catfish in the samples was 5.7. If the total population of fish in the pond is 2
lutik1710 [3]

Answer:10

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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