Answer: 0.4667
Step-by-step explanation:
According to 68–95–99.7 rule , About 99.7% of all data values lies with in 3 standard deviations from population mean (
).
Here , margin of error = 3s , where s is standard deviation.
As per given , we have want our sample mean 
to estimate μ μ with an error of no more than 1.4 point in either direction.
If 99.7% of all samples give an within 1.4 , it means that
Divide boths ides by 3 , we get
Hence, So must have 0.4667 as standard deviation so that 99.7 % 99.7% of all samples give an within 1.4 point of μ .
Answer:
Step-by-step explanation:
The degree of the function is odd, so the ends tend in opposite directions. The leading coefficient is negative, so the right end (as x gets large) will tend toward -∞. Then the left end tends toward +∞.
_____
If the degree is even, both ends tend in the same direction. That direction matches the sign of the leading coefficient.
The answer for this will be
2a(1-2a ²+3bc)
Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.
10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:
12.1/10 = 1.21 grams.
10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:
23.1/10 = 2.31 grams.
1 super bear weights to 2250 grams, hence the proportion between the <u>weight of a super bear and the weight of a mini-bear</u> is:
2250/1.21 = 1860.
The proportion between the <u>weight of a super bear and the weight of a regular bear</u> is:
2250/2.31 = 974.
The difference of proportions is given by:
1860 - 974 = 886.
It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.
More can be learned about proportions at brainly.com/question/24372153
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