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BARSIC [14]
2 years ago
7

The diagram shows two joint rectangles. The total area of the compound shape is 36cm

Mathematics
1 answer:
zzz [600]2 years ago
8 0

By algebraic approach we find that the <em>compound</em> shape is represented by the equation 2 · x² - 5 · x - 18 = 0 and the length of the <em>line</em> segment AB is 4.5 units.

<h3>How to find the total area of a compound shape</h3>

The total area of the compound shape is the sum of the areas of the two rectangles, whose entire expression is:

A = x · (x - 4) + 2 · x · (x - 2)     (1)

Then, we proceed to expand this expression by algebraic means:

A = x² - 4 · x + 3 · x² - 6 · x

A = 4 · x² - 10 · x

4 · x² - 10 · x - 36 = 0

2 · x² - 5 · x - 18 = 0

We need to solve the <em>quadratic</em> equation to determine the possible values of line segment AB. Please notice that lengths are nonzero positive integers:

2 · x² - 5 · x - 18 = 0

(x - 4.5) · (x + 2) = 0

There is only possibility for the length of the <em>line</em> segment AB: x = 4.5.

To learn more on quadratic functions: brainly.com/question/5975436

#SPJ1

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Read 2 more answers
Show 2 different solutions to the task.
laila [671]

Answer with Step-by-step explanation:

1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

1.n is odd integer

2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.

When n is negative even integer

n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.

Hence, the given expression is always even for every integer.

2.By mathematical induction

Suppose n=1 then n= substituting in the given expression

1+1=2 =Even integer

Hence, it is true for n=1

Suppose it is true for n=k

then k^2+k is even integer

We shall prove that it is true for n=k+1

(k+1)^1+k+1

=k^1+2k+1+k+1

=k^2+k+2k+2

=Even +2(k+1)[/tex] because k^2+k is even

=Sum is even because sum even numbers is also even

Hence, the given expression is always even for every integer n.

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3 years ago
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yKpoI14uk [10]
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bearhunter [10]

Answer:

y = x + 6.

Step-by-step explanation:

y = mx + c  where m = the slope of the line and c is the y-intercept.

So here m = 4/4 = 1 and c = 6, so it's:

y = 1x + 6.

3 0
3 years ago
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