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murzikaleks [220]
2 years ago
9

I need help explanation if possible

Mathematics
1 answer:
viva [34]2 years ago
3 0

Answer:

y = 16.

Step-by-step explanation:

The ratio of corresponding sides of similar triangles are the same.

The small and large triangles are similar ( - that is corresponding angles are congruent).

So 2/(2+8) = x / 20

2/10 = x/20

10x = 40

x = 4.

Therefore y = 20 -4 = 16.

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Please help :( Calculate each mountain path grade to the nearest percent.
wariber [46]
The grade of the path in the mountain is calculated by determining first the ratio between the rise over the run and multiplying the ratio by 100%. 

For Path A: 

                 grade = (rise / run) x 100%
                 grade = (1414/ 3535) x 100% = 40%

<em>Answer: 40%</em>

For Path B:
              grade = (rise / run) x 100%
              grade = (4.26 m/ 22 m) x 100% = 19.36%

Answer: 19.36%
                 
8 0
3 years ago
Arjun is twice as old as shriya. If 5 years ago his age was 3 times shriya s age ,then what is arjun s present age?
prisoha [69]

Answer:

20

Step-by-step explanation:

Let Shriya's current age b <em>x</em><em>.</em><em> </em>Arjun's current age will be <em>2</em><em>x</em>.

5 years ago, Arjun's age was <em>2</em><em>x</em><em>-</em><em>5</em><em> </em>and Shriya's age was <em>x</em><em>-</em><em>5</em><em>.</em>

Since Arjun's age was 3 times Shriya's age 5 years ago,

<em>2</em><em>x</em><em>-</em><em>5</em><em> </em>= <em>3</em><em> </em><em>(</em><em>x</em><em>-</em><em>5</em><em>)</em>

<em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em>

<em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em>

3 0
3 years ago
Given this number line, ab=
Nastasia [14]

Answer:

3

Step-by-step explanation:

7 -4 = 3

5 0
3 years ago
Let μ = 160 and σ = 16. find the z-score for the score, x = 150.
cricket20 [7]
Put the given values in the formula
z=\dfrac{x-\mu}{\sigma}
and evaluate.
  z = (150 -160)/16 = -10/16
  z = -5/8

The z-score for the score x=150 is -5/8 = -0.625.
8 0
3 years ago
Solve the following linear quadratic system of equations algebraically.<br><br> y=^2+3x-2<br> y+3=5x
USPshnik [31]

Answer:

x=1

y=2

Step-by-step explanation:

y=x^2+3x-2 , y+3=5x

Replace all occurrences of y in y+3=5x with x^2+3x-2.

(x^2+3x-2)+3=5x

y=x^2+3x-2

Add -2 and 3.

x^2+3x+1=5x

y=x^2+3x-2

Subtract 5x from both sides of the <u>equation.</u>

x^2+3x+1-5x=0

y=x^2+3x-2

Subtract 5x from 3x.

x^2-2x+1=0

y=x^2+3x-2

Rewrite 1 as 1^2.

x^2-2x+1^2=0

y=x^2+3x-2

Check that the middle <u>term</u> is two times the <u>product</u> of the numbers being squared in the first <u>term</u> and third <u>term</u>.

2x=2 · x · 1

y=x^2+3x-2

Rewrite the <u>polynomial</u>.

x^2-2 · x · 1 + 1^2=0

y=x^2+3x-2

Factor using the <u>perfect square</u>

<u>trinomial</u> rule a^2-2ab+b^2=(a-b)^2,

where a = x and b = 1.

(x-1)^2=0

y=x^2+3x-2

<u>Set</u> the x-1 equal to 0.

x-1=0

y=x^2+3x-2

Add 1 to both sides of the <u>equation</u>.

x=1

y=x^2+3x-2

Replace all occurrences of x in

y=x^2+3x-2 with 1.

y=(1)^2+3(1)-2

x=1

y=2

3 0
3 years ago
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