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3 years ago

Please help :( Calculate each mountain path grade to the nearest percent.

1 answer:

8 0

The grade of the path in the mountain is calculated by determining first the ratio between the rise over the run and multiplying the ratio by 100%.

For Path A:

grade = (rise / run) x 100%
grade = (1414/ 3535) x 100% = 40%

Answer: 40%

For Path B:
grade = (rise / run) x 100%
grade = (4.26 m/ 22 m) x 100% = 19.36%

Answer: 19.36%

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If m<1 = 38 then m<4 =

Mariana [72]

Answer:

If m<1 = 38 then m<4 = 38

Step-by-step explanation:

Both of the angles equal 38 degrees. This is true because the angles are vertical, vertical angles are angles opposite each other where two lines cross. Vertical angles are also always congruent, therefore the m<4=38.

4 0

3 years ago

7th Grade Math Please help -7 = 1/3 a Find the value of a

julsineya [31]

Answer:

$\huge\boxed{a=-21}$

Step-by-step explanation:

$-7=\dfrac{1}{3}a\to\dfrac{1}{3}a=-7\qquad|\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup\cdot\dfrac{1}{3\!\!\!\!\diagup}a=(-7)(3)\\\\a=-21$

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3 years ago

Create an equivalent expression that includes a set of parentheses that make the value of the expression 5. Remember, you can ha

Naily [24]

Answer: the Answer is 33

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3 years ago

What is the equation of the line that passes through the point (−4,−3) and has a slope of \frac{3}{4}

yawa3891 [41]

Answer:

y = $\frac{3}{4}$ x

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{3}{4}$ , then

y = $\frac{3}{4}$ x +c ← is the partial equation

To find c substitute (- 4, - 3) into the partial equation

- 3 = - 3 + c ⇒ c = - 3 + 3 = 0

y = $\frac{3}{4}$ x ← equation of line

8 0

3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

4 years ago