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zubka84 [21]
2 years ago
6

3. Look at the system below. What value could you use for "m" to make the lines

Mathematics
1 answer:
antoniya [11.8K]2 years ago
6 0

Answer:

what would make the lines perpendicular is using the first y as a another oart of the end of the second why

Step-by-step explanation:

y= = m2-6+8

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Answer:

x=7.5

Step-by-step explanation:

\frac{8}{5} =\frac{12}{x}

8x=60

x=7.5

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3 years ago
What is the value of the expression 1 1/4/20 4/5
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Answer:

  25/416

Step-by-step explanation:

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  (1 1/4)/(20 4/5) = (5/4)/(104/5) = (5/4)×(5/104) = (5×5)/(4×104) = 25/416

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Dang...H0: μ = 115 HA: μ ≠ 115 Sample mean = 120 Standard deviation = 25 Standard error of mean = σ / √ n Standard error of mean = 25 / √ 100 SE = 25/10 Standard error of mean 2.5 z = (xbar- μ ) / SE z = (120-115) / 2.5 z = 2 p-value = 2 P( z > 2) = 2(0.0228) = 0.0456 the data are statistically significant at level = .05, but not at level = .01. 2) H0: μ = 115 HA: μ ≠ 115 Sample mean = 119 Standard deviation = 25 Standard error of mean = σ / √ n Standard error of mean = 25 / √ 100 SE = 25/10 Standard error of mean 2.5 z = (xbar- μ ) / SE z = (119-115) / 2.5 z = 1.6 p-value = 2P( z > 1.6) = 2(0.0548) =0.1096 3) a statement about the population the researcher suspects is true, and is trying to find evidence for. 4) Sample mean = 80 Standard deviation = 20 Standard error of mean = σ / √ n Standard error of mean = 20 / √ 100 SE = 20/10 The Standard error of mean 2 Confidence interval 80-(2)(1.645) and 80+(2)(1.645) (76.7, 83.3)
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3 years ago
Write the equation of a line:
yawa3891 [41]

a)    Line parallel to the line 3x+5y=-10 is -6x-10y=9

b)    Line parallel to the line 2y-4x=5 and which goes through the point

       (3,7) is y= 2x-1.

c)      Line perpendicular to the line 8x+6y=-1 and which goes through the

        point (-2,1) is 4y= 3x+ 10


<h3>What is equation of line?</h3>

The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term. It is an equation of degree one, with variables x and y.

a) Equation parallel to 3x+5y=-10 is

    -6x-10y=9

So, it satisfies:  \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}

b)given equation into the form of y=mx+c,

     2y-4x=5

we can find the gradient of the line.

  2y= 5+4x

  y= \frac{5}{2} + 2x

Hence, the gradient is 2.

As, Parallel lines have the same gradient

Thus the line would also have a gradient of 2.

Substitute m=2 into the equation:

y= 2x +c

To find the value of c, substitute a pair of coordinates.

When x=3, y=7,

7= 2(3) +c

7= 6 +c

c=6-7

c= -1

So, equation of line be: y= 2x-1.

c) Given: 8x+6y=-1

     6y= -1-8x

     y= \frac{-1}{6} -\frac{4}{3}x

Hence, m= -\frac{4}{3}

We know, if two lines are perpendicular have m and m' as slope then,

m*m'=-1

\frac{-4}{3} *m'=-1

 m'= \frac{3}{4}

Now, y= \frac{3}{4} x +c

   

Put x= -1 and y=1

then, 1= \frac{3}{4} (-2) + c

         c= \frac{5}{3}

So,  y= \frac{3}{4} x + \frac{5}{2}

     4y= 3x+ 10

Learn more about equation of line here:

brainly.com/question/14577230

#SPJ1

5 0
3 years ago
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