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3 years ago

Plz help me with this math problem

Mathematics

1 answer:

Leya [2.2K]3 years ago

4 0

Answer:

The answer is B 1/4 + 2/6 + 4/10

Step-by-step explanation:

it just makes sense im sorry i cant explain :( i hope it helps either way xx <3

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Use partial fractions to find the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constan

BARSIC [14]

Answer:

125/6(In(x-25)) - 5/6(In(x+5))+C

Step-by-step explanation:

∫x2/x1−20x2−125dx

Should be

∫x²/(x²−20x−125)dx

First of all let's factorize the denominator.

x²−20x−125= x²+5x-25x-125

x²−20x−125= x(x+5) -25(x+5)

x²−20x−125= (x-25)(x+5)

∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx

x²/(x²−20x−125) =x²/((x-25)(x+5))

x²/((x-25)(x+5))= a/(x-25) +b/(x+5)

x²/= a(x+5) + b(x-25)

Let x=25

625 = a30

a= 625/30

a= 125/6

Let x= -5

25 = -30b

b= 25/-30

b= -5/6

x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)

∫x²/(x²−20x−125)dx

=∫125/6(x-25) -∫5/6(x+5) Dx

= 125/6(In(x-25)) - 5/6(In(x+5))+C

4 0

4 years ago

The length of a rectangle is 6 meters shorter than its

rewona [7]

Answer:

Width = 14m

Step-by-step explanation:

width = w

length = w - 6

area: w(w-6) = 112

w^2 - 6w = 112

14 x 14 = 196

6 x 14 = 84

196 - 84 = 112

6 0

3 years ago

If four points are collinear are they coplanar

kap26 [50]

It is False , because they could be in a common plane but they do not form a single line

6 0

3 years ago

What is the area of triangle HGF? Round your answer to the nearest tenth of a square centimeter. Recall that you need to round u

denpristay [2]

Answer:

9.8

Step-by-step explanation:

The formula for the area of a triangle is a=bh/2, where a is area, b, is the base, and h is the height. If we substitute the values in the question in the equation, we get:

a=(6.5*3)/2

a=19.5/2

a=9.75

a≈9.8

7 0

3 years ago

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

3 years ago