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AlexFokin [52]
3 years ago
12

Explain wether the graph represents a function.

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

The vertical line test can be used to determine whether a graph represents a function. ... If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output. A function has only one output value for each input value.

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3241004551 [841]

Answer:

4

Step-by-step explanation:

The numbers you have are 2, 2, 3, 4, 8, 8, 8

First, cross out 2 on the very left and 8 on the very right.

Then you are left with 2, 3, 4, 8, 8, Then cross out the 2 on the left and the 8 on the right, and you are left with 3, 4, 8. Cross out the 3 and 8, and you are left with the median, 4.

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3 years ago
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Complete the two-column proof.
Nataliya [291]

The <em><u>correct answers</u></em> are:

substitution property; subtraction property of equality; division property of equality; and reflexive property.

Explanation:

The difference between the given statement and the first statement is that 11x is replaced with 88.  This is because we are told that x=8; 11(8) = 88.  Substitution has been used here.

The difference between the first step and the second step is that 88 is no longer on the left hand side and the right hand side is -89.  This is because to cancel 88, it has been subtracted from each side of the equation.  This is the subtraction property of equality.

The difference between the second step and the third step is that -6 is no longer on the left side and the right hand side is 89/6.  This is because to cancel -6 both sides were divided by -6.  This is the division property of equality.

The difference between the third step and the last step is that the 89/6 and y have been flipped around the equals sign.  This is the reflexive property.

6 0
4 years ago
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Ira Lisetskai [31]

Answer:

False

Step-by-step explanation:

Sorry for the lat reply hopefully you still have that question ready. But basically in order for these equations to be considered inverses of one another it has to map its domain value and switch it to the range value and in this case it does not match the inverse when graphed.

7 0
3 years ago
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