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miskamm [114]
2 years ago
14

Find m/EGD. (measurement in degrees)

Mathematics
2 answers:
Wewaii [24]2 years ago
6 0

Answer:

\huge\boxed{\bf\:30^{\circ}}

Step-by-step explanation:

We need to find m ∠EGD.

From the given figure, we can see that, ∠BGA & ∠EGD are vertically opposite angles (opposite angles that share the same vertex ⟶ G).

Also, vertically opposite angles are equal to each other.

Given,  ∠BGA = 30°

So,  ∠EGD =  ∠BGA = 30°.

\rule{150pt}{2pt}

Stella [2.4K]2 years ago
6 0

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

from the given figure , we can easily see that ∠AGB = ∠EGD

this is because these angles are <u>vertically</u><u> </u><u>opposite </u><u>,</u><u> </u><u>i.</u><u>e</u><u>.</u><u> </u><u>,</u><u> </u><u>the </u><u>angles </u><u>that </u><u>share </u><u>the </u><u>same </u><u>vertex </u><u>!</u><u> </u><u>also </u><u>,</u><u> </u><u>it's</u><u> </u><u>known </u><u>that </u><u>two </u><u>angles </u><u>that </u><u>are </u><u>vertically</u><u> </u><u>opposite</u><u> </u><u>are </u><u>equal </u><u>to </u><u>each </u><u>other </u><u>!</u>

\therefore \: \bold{\angle \:  EGD= 30\degree}

hope helpful ~

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A plane flew 720 mi with a steady 30 mi/h tailwind. The pilot then returned to the starting point, flying against that same wind
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