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Mashcka [7]
3 years ago
11

ASAP!! HEEELPPPP!!

Mathematics
1 answer:
alekssr [168]3 years ago
8 0

I believe the answer is B

Hope This Helps!     Good Luck!!

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14) The perimeter of this isosceles triangle is represented by the
Galina-37 [17]

The isosceles triangle is missing so i have attached it.

Answer:

Length of unknown side = 5p + 6

Step-by-step explanation:

In isosceles triangle, two of the sides are equal. In the attached triangle, we see that one of the equal sides is given as 5p + 3.

Thus,the second equal side is also 5p + 3.

Now, perimeter of a triangle is the sum of the three sides.

We have two sides and let the third side be denoted as x.

Thus;

Perimeter = (5p + 3) + (5p + 3) + x

We are given perimeter = 15p + 12

Thus;

(5p + 3) + (5p + 3) + x = 15p + 12

10p + 6 + x = 15p + 12

Rearranging, we have;

x = 15p - 10p + 12 - 6

x = 5p + 6

4 0
3 years ago
“x” means what in math equations? I’m not the best at math :/
tino4ka555 [31]

Answer:

X is just the variable or missing edge, side, angle .etc that you are looking for

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!
Nadusha1986 [10]
M(meters) = 0.9144*y(yards)
4 0
3 years ago
Find the value of x. Everything is in the photo.
Elan Coil [88]

Answer:

27

Step-by-step explanation:

Note that since VX and XZ are both line segments, <VWX and <XYZ both equal 180 (also known as a straight angle). Also, note that the sum of the angles in a triangle are 180 degrees. Now, let’s start.

Finding angles of the triangle:

<WYX = <XYZ - <WYZ = 180 - 4x

<XWY = <XWV - <VWY = 180 - 6x

Using the sum of angles in a triangle and substituting these values in:

180 = <X + <WYX + <XWY = 90 + (180 - 4x) + (180-6x) = 450 - 10x

270 = 10x

<em>27 = x</em>

We are done! I hope this helps! :)

4 0
3 years ago
What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!
ipn [44]

Answer:

x = 1 + \sqrt5, x = 1 - \sqrt5

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: ax^2 + bx + c = 0

Quadratic Formula: x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}

Given our Equation: g(x) = x^2 - 2x - 4

  • a = 1
  • b = -2
  • c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>
  • x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}
  • x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}
  • x = \frac{2\pm\sqrt{4 +16}}{2}
  • x = \frac{2\pm\sqrt{20}}{2}
  • x = \frac{2\pm\sqrt{4 * 5}}{2}
  • x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}
  • x = \frac{2\pm2\sqrt5}{2}
  • x = 1 + \sqrt5, x = 1 - \sqrt5
7 0
2 years ago
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