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3 years ago

ASAP!! HEEELPPPP!!

Mathematics

1 answer:

alekssr [168]3 years ago

8 0

I believe the answer is B

Hope This Helps! Good Luck!!

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How much heavier is a 9 1/8 pound box than a 2 5/6 pound box?

tatuchka [14]

So let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly subtract this given equation. We need to convert the two given number into a fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6

Now, we have 2 fractions with unlike denominator. In order to get a common denominator, we have to find their least common factor.

=> 73 - 17 = 73 x 6 - 17 x 8 
 8 6 8 x 6 6 x 8
=> 438 – 136 Now, we have the same denominator, subtract
 48 48
=> 302 or 151
 48 24
=> 6 7
 24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.

4 0

3 years ago

At Billy‘s preschool they have bicycles and tricycles with a total of 57 wheels. The number of bicycles is three less than three

ikadub [295]

Use b for bicycles b and t for tricycles.

We know that each bicycle has 2 wheels, and each tricycle has 3 wheels, and if the entire number of wheels is 57, that means the

equation would be: 2b + 3t = 57

We can "separate" b by calling it "25 - t" as an alternative,

2(25 - t) + 3t = 57, or

50 - 2t + 3t = 57,

or 50 + t = 57, so

t = 7 So there must be 18 bicycles and 7 tricycles.

CHECKING:You can check this out by multiplying 7 tricycles x 3 wheels, which is 21,

and 18 bicycles x 2 wheels, which is 36

36 + 21 = 57

6 0

3 years ago

Find the general solution of (x+3)y’=2y

gregori [183]

Answer:

$y=C(x+3)^2$

Step-by-step explanation:

We are given:

$\displaystyle (x+3)y^\prime=2y$

Separation of Variables:

$\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}$

So:

$\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx$

Integrate:

$\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx$

Integrate:

$\displaystyle \ln|y|=2\ln|x+3|+C$

Raise both sides to e:

$|y|=e^{2\ln|x+3|+C}$

Simplify:

$|y|=(e^{\ln|x+3|})^2\cdot e^C$

So:

$|y|=C|x+3|^2$

Simplify:

$y=\pm C(x+3)^2=C(x+3)^2$

5 0

3 years ago

Juan runs a charity run to raise money for a local animal shelter and his friend pledges $0.75 per mile that Juan runs. If Juan

givi [52]

Answer:

2.62 dollars

Step-by-step explanation:

6 0

2 years ago

(Inequalities) what do you have to do when multiplying or dividing by a negative number?

Rashid [163]

Answer:

When we multiply or divide by a negative to solve an inequality, it's the same as multiplying or dividing by a negative to solve a regular equation! Just remember to multiply or divide both sides by the same quantity, then simplify! Remember, when multiplying or dividing by a negative YOU MUST FLIP THE INEQUALITY SIGN.

Step-by-step explanation:

You are welcome.

And I hope this helps. :)

4 0

3 years ago

Read 2 more answers