Question

Help me please i don't know what to do

Answer 1

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

$(x-7)(x+2) = 0$

FOIL:

$x^2 + 2x - 7x - 14 = 0$

Simplify:

$x^2 - 5x - 14 = 0$

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

$(x-3)^2=0$

FOIL:

$x^2 - 3x - 3x +9 = 0$

Simplify:

$x^2 - 6x + 9 = 0$

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

$-x^2-x-3=0$

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

$(x+1)(x-1)=0$

This is a perfect square

FOIL:

$x^2-1=0$

a = 1, b = 0, c = -1

e. x-int at $\sqrt{3} , -\sqrt{3}$

our equation will factor to:

$(x+\sqrt{3} )(x-\sqrt{3)} =0$

This is also a perfect square

FOIL and you will get:

$x^2 - 3 = 0$

a = 1, b = 0, c = -3