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goldfiish [28.3K]
3 years ago
11

PLEASE ANSWER!!!! A certain transformation is applied to a line segment. The new segment shifted to the left within the coordina

te plane. What was the transformation? *
A rotation
A reflection
A translation
It cannot be determined.
Mathematics
2 answers:
taurus [48]3 years ago
6 0

translation because you are moving it

bogdanovich [222]3 years ago
4 0

Answer:

Translation

Step-by-step explanation:

A translation is a geometric transformation that moves every point of a figure by the same distance in a given direction.

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iren2701 [21]
The sum of the interior angles of a triangle is 180 degrees

2x-9+3x+x+3=180
6x-6=180
6x=186
x=31

A=2(31)-9
A=62-9
A=53
8 0
3 years ago
Which expression is equivalent to -2( x-7 )?
AnnyKZ [126]

Answer: -2x+14

Step-by-step explanation: use the distributive property. -2 times x and -2 times -7. -2x+14

5 0
2 years ago
Read 2 more answers
Is 68 prime because i am doing homework and im stuck on this and it is very hard so help me please
BlackZzzverrR [31]

If  68  is a prime number, then the only factors it has are  1  and  68.
If it has any other factors besides  1  and  68, then it's NOT prime.

Right away, without any higher math, you can look at just the last digit
in 68 .  The last digit is '8'.  That tells you that '68' is an even number,
and THAT tells you that '2' must be one of its factors.  So '68' is not a
prime number.

The factors of  68  are  1,  2,  4,  17,  34, and  68 .    

68  has four more factors besides  1  and  68, so it's not a prime number.

8 0
3 years ago
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A diagonal of a square is 36 feet long. What is the area of the square?
Rzqust [24]
So you can you the Pythagorean theorem to solve this problem.

if each side of the square is a certain length x, then the square is made up of two right triangles.

the sides adjacent to the right angle are length x while the hypoteneus is the diagonal whcih measures 36 feet.

a^2 + b^2 = c^2

x^2 + x^2 = 36^2

2x^2 = 1296

x^2 = 648

x = 25.456

area of a square = x^2 = 648 ft^2
3 0
3 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
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