Answer:
Step-by-step explanation:
We have to diagonalize the matrix
![\left[\begin{array}{ccc}1&-1&0\\5&1&4\\0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%260%5C%5C5%261%264%5C%5C0%261%261%5Cend%7Barray%7D%5Cright%5D)
we have to solve the expression

Thus, by applying the determinant we obtain the polynomial



and the eigenvector will be

HOPE THIS HELPS!!
Step-by-step explanation:
1) x/20 = -9
By cross multiplication,
x = -180
2) -168 = -14k
k = -168/-14
k = 12
3) -5m = -50
m = 10
4) -320 = -20n
n = 16
5) -4 = x - 5
x = 1
6) -6(-8 + n) = -54
42 - 6n = -54
-6n = -54 -52
6n = 106
n = 17.6
7) 3(x - 9) = -3
3x - 27 = -3
3x = 24
x = 8
8) 9k + 3 = -78
9k = -81
k = -9
9)4 + (n/4) = 8
By taking LCM,
16 + n/4 = 8
16 + n = 32
n = 16
10) -5r + 7 = -73
-5r = -80
r = 16
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>
Answer:
B
Step-by-step explanation:
I'm not sure if it's right but you can try it
This problem can be solved using dimensional analysis.
