K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE


g is taken as 9.81
5/13
The x value is negative (second quadrant). 13 is the hypotenuse. So the missing side is 13^2 = (-12)^2 + y^2.
Sin theta is the opposite (5) over hypotenuse (13).
Answer:
AB = CD
BC = DA
Step-by-step explanation:
Since 3x+2 = 5x-2, solving for x yields 2. Since BC = 4x+1 = DA, BC and DA both equal 4(2)+1 = 9.