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Fudgin [204]
3 years ago
7

K - 2( k - ( 2- k ) - 2

Mathematics
1 answer:
mamaluj [8]3 years ago
5 0
Assuming the missing parenthesis is at the end the simplified answer should be k-8
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What is the perimeter of a triangle if the lengths of the sides
Leno4ka [110]

Answer:

P=x+18

Step-by-step explanation:

a=8

b=x

c=10

P=8+x+10

8 0
3 years ago
What is the smallest 6 digit palindrome that is divisible by 99
Scorpion4ik [409]

Answer:

  • 108801

Step-by-step explanation:

<u>6-digit palindrome is the number n the form of:</u>

  • xyzzyx

<u>This is divisible by 11 by default as the sum of the digits in odd placed is same as sum of the number in even places (remember the divisibility rule by 11):</u>

  • x + z + y = y + z + x

Now, in order to be divisible by 99, the number must be divisible by 11 and 9.

According to divisibility rule by 9 the sum of all digits must be divisible by 9. <u>You can see In our case we need to have (the minimum):</u>

  • x + y + z = 9

<u>The smallest number we could get is when x is minimum, y is minimum, so:</u>

  • x = 1, y = 0, then y = 8

<u>The number we get is:</u>

  • 108801

<u>Proof:</u>

  • 108801/99 = 1099
4 0
3 years ago
Read 2 more answers
If a x 10n is scientific notation, then a must be between 1 and ___.
posledela

Answer:

b. 100

Step-by-step explanation:

usatestprep approved

5 0
3 years ago
Find the measures of angles x and y please!?
kenny6666 [7]

Answer:

y: 139 x: 139 too

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.
suter [353]

Answer:

The width of the photo is 4w^2+6w+4.

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

6w^2+8

The photo is covered by a frame border and the width of the border is

w^2-3w+2

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})

\text{Width of the photo}=6w^2+8-2(w^2-3w+2)

\text{Width of the photo}=6w^2+8-2w^2+6w-4

\text{Width of the photo}=4w^2+6w+4

Therefore the width of the photo is 4w^2+6w+4.

4 0
3 years ago
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