N + d = 20....n = 20 - d
0.05n + 0.10d = 1.35
0.05(20 - d) + 0.10n = 1.35
1 - 0.05d + 0.10d = 1.35
-0.05d + 0.10d = 1.35 - 1
0.05d = 0.35
d = 0.35/0.05
d = 7 <==== 7 dimes
n + d = 20
n + 7 = 20
n = 20 - 7
n = 13 <=== 13 nickels
Answer:
n+4=32
Step-by-step explanation:
The initial number n gets additional 4 students making the new total number of students to be 32. Therefore, this situation can be represented as
n+4=32
To get the actual number of students before the additio, we make n the subject of formula hence
n=32-4
n=28
Therefore, the initial number was 28 and the equation is n+4=32
Since no choices were provided, the equation that can be modified is n+4=32
Any number that can be writen as a fraction example: 0.75, -15, 0, 9
Answer:
6 blooms
Step-by-step explanation:
40 x 15%
40 x 0.15 = 6
Answer:
x=0
Step-by-step explanation:
solve for x by simplifying both sides of the equation then isolating the variable
