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2 years ago

Application of percentages

Mathematics

1 answer:

musickatia [10]2 years ago

4 0

Answer:

600

Step-by-step explanation:

convert 25% to a a decimal then divide 150 by .25

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What is the positive solution to the equation 0 = –x2 + 2x + 1? Quadratic formula: x = StartFraction negative b plus or minus St

katrin [286]

Answer:

x = 2 + √2

x = 2 - √2

Step-by-step explanation:

- x² + 2x + 1 = 0

x² - 2x - 1 = 0

Here,

a = 1

b = - 2

c = - 1

Now,

Discriminant

D = b² - 4ac

= (-2)² - 4(1)(-1)

= 4 + 4

= 8

=2√2 > 0

Real and Distinct roots

x = - b +- √b² - 4ac/2a

= - (-2) +- √ = (-2)² - 4(1)(-1)/2(1)

= 2 +- √4 + 4/2

= 2 +- √8/2

= 2 +- 2√2/2

= 2 +- √2

x = 2 + √2 or x = 2 - √2

7 0

3 years ago

Can anyone help me with this?

vivado [14]

The answer is the second one

4 0

3 years ago

Read 2 more answers

PLS HELP RQ!!!!!!!!!!!!!11

Naya [18.7K]

Answer:

3 3/4 cubic inches

Step-by-step explanation:

2.5*1.5*1

4 0

3 years ago

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Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of

prohojiy [21]

Answer:

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

Step-by-step explanation:

Information given

$\bar X¿ 17.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s¿4.2 represent the sample standard deviation

n¿65 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=65-1=64$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

8 0

3 years ago

Use distributive property for 3.2= 4/5(b - 5)

tigry1 [53]

I hope this helps :)

5 0

3 years ago