3 years ago

What is the sum of the geometric sequence -3,18,-108,.. if there are 7 terms?

Mathematics

1 answer:

andreev551 [17]3 years ago

5 0

Answer:

$S_{7}$ = - 119973

Step-by-step explanation:

The sum to n terms of a geometric sequence is

$S_{n}$ = $\frac{a(r^n-1)}{r-1}$

where a is the first term and r the common ratio

Here a = - 3 and r = 18 ÷ - 3 = - 6 , thus

$S_{7}$ = $\frac{-3(-279936-1)}{-6-1}$

= $\frac{-3(-279937)}{-7}$

= $\frac{839811}{-7}$

= - 119973

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asambeis [7]

Answer:

Step-by-step explanation:

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3 years ago

If sine ⁡theta equals negative 8/17 and the terminal side of theta lies in quadrant IV, find cosine ⁡ theta .

Lelechka [254]

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Since $\sin\theta=-\dfrac8{17}$ , it follows that

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