Answer:
q=4p-14
Step-by-step explanation:
5q-4p+6=4q-8
5q-4q-4p=-8-6
q-4p=-14
q=-14+4p
q=4p-14
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
This is a linear equation (the graph is a line)
To identify the graph find out the intercepts
<u><em>Find out the y-intercept</em></u>
The y-intercept is the value of y when the value of x is equal to zero
For x=0
The y-intercept is the point (0,-4)
<u><em>Find out the x-intercept</em></u>
The x-intercept is the value of x when the value of y is equal to zero
For y=0
The x-intercept is the point (5.33,0)
therefore
The graph in the attached figure
Answer and Step-by-step explanation:
Although the question is not complete, but with the context of the question, they are most likely going to ask for the total distance travelled or the total time or speed. So let's work on that.
Total time travelled = (3 + 5 + 4) = 12mins
Total speed travelled = (0.50 + 0.00 + 0.40)miles/min = 0.90mile/min
The 0.00 represents the period he was at rest admiring an antique car. At this moment, he was not moving so his speed is 0.
Total distance travelled = total speed x total time = 0.90miles/min x 12min = 10.8miles
Answer:
17.9 m/s
Step-by-step explanation:
Volume of the slick = 0.5 x π r² h--------------------------------- (1)
Where r = radius of slick
h = thickness of slick, 10⁻⁶m
If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)
V = 0.5 x π r² h
0.5= 0.5 x π x r² x 10⁻⁶
r² = 10⁶/ π
r = 10³/√π
dV/dt = πrh dr/dt + 0.5π r² dh/dt----------------------------------- (2)
Asumming the film thickness is constant , equation (2) becomes
dV/dt = πrh dr/dt-------------------------------- (3)
dV/dt = 0.1m³/day
r= 10³/√π
dr/dt= rate of expansion of the slick
Substituting into (3);
0.1 = π x 10³/√π x 10⁻⁶ x dr/dt
dr/dt = 0.1 x 10⁶/ ( π x 10³/√π)
= 17.9479 m/s
≅ 17.9 m/s
