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2 years ago

Find the area in the shaded region.

Mathematics

2 answers:

irinina [24]2 years ago

7 0

The answer should be 227 ft

Katen [24]2 years ago

5 0

Yes I agree it should me 277ft

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I might mark brainliest I just need help

Artemon [7]

Answer:

i think you have to measure your diagram with a protector to find the angles

8 0

2 years ago

What is the equation of the following line? Be sure to scroll down first to see all answer options.

Harrizon [31]

<h3><u>Answer:</u></h3>

Hence, the equation of line is:

y= -6x

<h3><u>Step-by-step explanation:</u></h3>

Clearly from the graph we could see that the line passes through the point (0,0) and (-1/2,3).

Also we know that the equation of a line passing through (a,b) and (c,d) is given as:

$y-b=\dfrac{d-b}{c-a}\times (x-a)$

Here we have:

(a,b)=(0,0) and (c,d)=(-1/2,3)

Hence, the equation of line is:

$y-0=\dfrac{3-0}{-\dfrac{1}{2}-0}\times (x-0)\\\\\\\\y=\dfrac{3}{\dfrac{-1}{2}}\times x\\\\y=3\times (-2)\times x\\\\y=-6x$

Hence, the equation of line is:

y= -6x

6 0

2 years ago

Read 2 more answers

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Whats a fraction thats equivalent to 3/12

Ad libitum [116K]

Answer:

1/4

Step-by-step explanation:

Yes

6 0

3 years ago

Read 2 more answers

Rearrange the following numbers in order from least to greatest.

inysia [295]

Answer:

-25, -14, -10, -9, -8, -7, 0, 2

Step-by-step explanation:

You do thing and it work

5 0

3 years ago

Read 2 more answers