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Allisa [31]
3 years ago
6

Given: ΔАВС, m∠ACB = 90°,m∠ACD = 30°,AD = 8 cm. Find: CD, Perimeter ΔABC Please solve!

Mathematics
1 answer:
sukhopar [10]3 years ago
8 0
If m ACD = 30 => m DCB = 60.
In triangle ACD:
sin 30^{o}=sin  \frac{AD}{AC} =\ \textgreater \   \frac{1}{2}  =  \frac{8}{AC} =\ \textgreater \  AC=16

CD= 8 \sqrt{3}
BC= 16\sqrt{3}
AC^{2}+CB^{2}=AB^{2} => AB=\sqrt{1024}=32.
=> P=16+32+16 \sqrt{3}=48 +16 \sqrt{3}.

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