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Allisa [31]
3 years ago
6

Given: ΔАВС, m∠ACB = 90°,m∠ACD = 30°,AD = 8 cm. Find: CD, Perimeter ΔABC Please solve!

Mathematics
1 answer:
sukhopar [10]3 years ago
8 0
If m ACD = 30 => m DCB = 60.
In triangle ACD:
sin 30^{o}=sin  \frac{AD}{AC} =\ \textgreater \   \frac{1}{2}  =  \frac{8}{AC} =\ \textgreater \  AC=16

CD= 8 \sqrt{3}
BC= 16\sqrt{3}
AC^{2}+CB^{2}=AB^{2} => AB=\sqrt{1024}=32.
=> P=16+32+16 \sqrt{3}=48 +16 \sqrt{3}.

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In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?
valina [46]
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8 0
3 years ago
Read 2 more answers
Let f(x)=2.912345x^2+3.131579x-0.099999
Rudiy27
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f(x) = 2.912345x²<span>+3.131579x-0.099999
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C.) The percentage error is equal to:

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D.) If x is a large number, for example x=10 or x=20, then g(x) would be an overestimate. This is because the value of x is raised to the power of 2. So, as the x increases, the corresponding function would increase exponentially. Even at x=4, g(x) is already an overestimate. What more for larger values of x? That means that the gap from the true answer f(x) would increase.
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2 years ago
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I hope this helped :)
3 0
3 years ago
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motikmotik

To solve this we need to use this formula:

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