Answer:
multicellular animal,plant,fungi,microorganisms
In order to determine the results from a father who is homozygous recessive for the tongue rolling trait, T, and a mother who is heterozygous for the trait, a Punett square can be used to determine both the resulting genotype (allele combination) and phenotype (observable characteristics). The results are 50% Tt and 50% tt. Thus, the cross would result to 1:1 ratio of tongue rolling to non-tongue rolling offsprings.
Answer:
The chance of having a Child who is a Heterozygote is 50% , The chance of having a child that will completely come down with Alpers syndrome is 0%
Explanation:
Jack has a history of Alpers in his family
Jill has no history
lets assume Jack is a carrier : Ab ( because that is how he could have survived the first 10 lethal years )
Jill : AA
Therefore the probability/chance of Jack and Jill having a child with Alpers ( carrier ) syndrome will be 50 % as shown below
AA * Ab = AA , Ab, AA, Ab
The child produced by Jack and Jill will only be a carrier of the syndrome and not completely affected by the syndrome
Leaders should employ all available active and passive surveillance measures to
identify Soldiers who may be engaging in high-risk behavior and to <span> identify Soldiers who may be at risk based on behavior and stress indicators.
</span><span>The unit commander is the critical agent for injury prevention and is responsible for establishing interventions and monitoring their effect and he/she is responsible for this.</span>
