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Ivenika [448]
2 years ago
12

Which magazine can help the public to determine the best technology to buy?

Computers and Technology
2 answers:
fredd [130]2 years ago
8 0
Consumer Reports Of Course :D :v
mamaluj [8]2 years ago
8 0
Consumer Reports without a doubt
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Tyra is peer conferencing about her project with a friend. Tyra's friend provided feedback that Tyra does not agree with. What s
natulia [17]

Answer:

Be kind and thankful

Explanation:

If Tyra does not agree with her friend's feedback, she does not have to say it outrightly to her friend. She has to use softer words to disagree. This is where being kind comes in.

Her friend has made efforts by providing this feedback Even if it is not exactly what she wants to hear. It would be polite for her to say thank you.

Then she has to respectfully disagree to avoid coming off as someone who is totally unreceptive of the opinion of others.

6 0
2 years ago
An enhancement to a computer accelerates some mode of execution by a factor of 10. The enhanced mode is used 50% of the time, me
Ann [662]

Answer:

The answer is "5.5 and 90.90%"

Explanation:

For point 1:

To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty (50 \%) and the increased stages (50 \%).

Although not enhanced, this would take almost as long (50 \%) and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as 500 \%. Thus the corresponding total speed without enhancement is =50\% + 500\% = 550\%.

Its overall speed is:

=\frac{\text{Accelerated runtime}}{ \text{accelerated  runtime}} = \frac{550 \%}{ 100 \%}= 5.5

For point 2:

We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:

\text{Vectorized fraction}= \frac{\text{Overall velocity}\times \text{Accelerated acceleration}-\text{Accelerated acceleration}}{\text{Overall acceleration} \times \text{Accelerated acceleration}-\text{Overall acceleration}}

                              = \frac{5.5  \times 10 -10 }{ 5.5 \times 10 - 5.5}\\\\=\frac{45}{49.5}\\\\=0.9090\\\\=90.90\%

5 0
2 years ago
¿En qué año se funda lego?
pochemuha
August 10, 1932 in Billund, Denmark
7 0
2 years ago
The World Wide Web Consortium enforced a stricter set of standards in a different version of Hypertext Markup Language (HTML) ca
Eva8 [605]

Answer:

Option B is the correct answer for the above question

Explanation:

XHTML is an advanced version of HTML language which is recommended by W3C. It set the standard in 26-JAN-2000 for the XHTML which belongs to the family of HTML. XHTML is made with the help of XML and also used like XML. It used to create more secure websites.

The Above question asked about the W3C recommendation but the above paragraph described that XHTML is a W3C recommendation. Hence Option B is the correct choice answer. while the other is not because--

  • Option A suggests HTML 4.01 which is the updated version of HTML only.
  • Option C suggests XML which is used to data transfer only.
  • Option D suggests about DHTML but XHTML is a W3C recommendation
5 0
2 years ago
Create a game that rolls two dies (number from 1 to 6 on the side) sequentially for 10 times (use loop). If at least once out of
Alex73 [517]

Answer:

Explanation:

The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"

import java.util.Random;

class Brainly {

   public static void main(String[] args) {

       UseRandom useRandom = new UseRandom();

       boolean youWin = false;

       for (int x = 0; x<10; x++) {

           int num1 = useRandom.getRandom(6);

           int num2 = useRandom.getRandom(6);

           if ((num1 + num2) == 10) {

               System.out.println("Number 1: " + num1);

               System.out.println("Number 2: " + num2);

               System.out.println("You Win");

               youWin = true;

               break;

           }

       }

       if (youWin == false) {

           System.out.println("You Lose");

       }

   }

}

class UseRandom{

   public int getRandom(int n)

   {

       Random r=new Random();

       int rand=r.nextInt(n);

       return rand;

   }}

8 0
2 years ago
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