Answer/Step-by-step explanation:
1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:
Side CD and side DG.
2. Vertex of <2 is the endpoint at which two sides meet to form <2.
Vertex of <2 is D.
3. Another name for <3 is <EDG
4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.
5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.
6. m<5 = 42°
m<1 = 117°
m<CDF = ?
m<5 + m<1 = m<CDF (angle addition postulate)
42° + 117° = m<CDF (Substitution)
159° = m<CDF
m<CDF = 159°
7. m<3 = 73°
m<FDE = ?
m<FDG = right angle = 90°
m<3 + m<FDE = m<FDG (Angle addition postulate)
73° + m<FDE = 90° (Substitution)
73° + m<FDE - 73° = 90° - 73°
m<FDE = 17°
The solution is (-2,4) she right both have the same solution because if you solve both of them you will get (-2,4)
Answer:
The arc measure, x, that the satellite can see is 160°
Step-by-step explanation:
Given that the two tangents intersect at a point outside the with circle center O
The angle formed between between the two tangent = 20°
The first arc formed is measured as x°, which is the arc opposite the point where the two tangents meet = The arc the satellite can see
The angle x is given by the relationship;
x = 2 × (90 - v/2)
Where;
v = The angle formed at the point where the two tangent meet = 20°
Therefore;
x = 2 × (90 - 20/2) = 2 × (90 - 10) = 2 × 80 = 160°
The arc measure, x, that the satellite can see = 160°.
Answer: the answer is 30 kg
explanation: I did the the test
10
the hypotenuse is the largest side
so out of 6,8,10
10 is the largest