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-Dominant- [34]

2 years ago

9

Once the boat is 2,500 feet away from the port, it is no longer your responsibility to track it. will the boat be 2,500 feet awa

y after two minutes? the speed of the boat is 30 ft per second

1 answer:

sweet [91]2 years ago

4 0

Answer:

Step-by-step explanation:

30*60=1800ft/minute

2500-1800=700

700/30=23.3333333333

60+23.3333333333=83.3333333333 seconds

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Is 0.44 rational or irrational

ArbitrLikvidat [17]

0.44 rational

/0.4 irrational

/0.44 irrational

8 0

3 years ago

Read 2 more answers

What is the value of log279?<br> -3/2, -2/3, 2/3, 3/2

kaheart [24]

Answer:

2/3

Step-by-step explanation:

log27(9)

Factor the number: 27=3³

= log3³(9)

Apply log rule: loga^b(x) - 1/b loga(x).

log3³(9) =1/3 log3³(9)

=1/3 log3³(9)

Factor the number: 9=3²

=1/3 log3³(3²)

Apply log rule: loga(a^b) =b

log3 (3²) =2

1/3×2

=2/3

3 0

2 years ago

The perimeter of the triangle shown is 412 meters. Find the length of each side.

Fudgin [204]

Answer:

x meters= 35

5x meters= 175

6x - 8 = 202

Step-by-step explanation:

x + 5x + (6x - 8)= 412

12x - 8= 412

12x = 412 + 8

12x = 420

x= 35

5x = 35× 5

= 175

6x - 8= 6(35) - 8

= 210 - 8

= 202

7 0

2 years ago

For circle O, mCD=125° and m

Burka [1]

CA is a diameter of the circle, so $m\widehat{AC}=180^\circ$ , which means $m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ$ . Then $m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ$ .

This means $m\angle CBO=55^\circ-35^\circ=20^\circ$ . Also, if $m\angle AOB=55^\circ$ , then $m\angle BOC=180^\circ-55^\circ=125^\circ$ , which in turns tells us that $m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ$ .

3 0

2 years ago

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

<em>Hence, the smallest sum is 2</em>

3 0

3 years ago