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olganol [36]
2 years ago
7

Find the slope of the line containing the pair of points. ​(​7,​4) and ​(6​,-9​)

Mathematics
2 answers:
Rudiy272 years ago
4 0

Answer:

<u>-9 -4</u>

6-7

=13

Step-by-step explanation:

lesya [120]2 years ago
3 0

Answer:

13

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

   = ( -9-4)/(6-7)

   = -13/-1

  = 13

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Artist 52 [7]
The answer whould be like this

305 - 3d
8 0
3 years ago
I need help in "Matlab' with how to "Create a column vector from 15 to -25 with a step size of 5"
Alekssandra [29.7K]

Answer:

x=[15:-5:-25]'

Step-by-step explanation:

In order to create a vector you need to use this command:

x = [j:i:k]'

This creates a regularly-spaced vector x using i as the increment between elements. j is the initial value and k is the final value. Besides you need to add the character ' at the end in order to convert the arrow vector in a column vector

5 0
3 years ago
Which expression is equal to 4 (2+3) ?<br><br><br> 1. 2+12<br> 2. 4+5<br> 3. 8+3<br> 4. 8+12
allsm [11]
4. 8+12=20

4 (2+3)
First you add 2+3 and get 5
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5 0
3 years ago
Read 2 more answers
Given: sinθ = -3/5, θ is a third quadrant angle, and tan φ = -7/24, φ is a second-quadrant angle; find cos(θ + φ])
Natali [406]

Answer:

First option: cos(θ + φ) = -117/125

Step-by-step explanation:

Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.

Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.

Therefore:

cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)

cos(θ + φ) = (-96/125) - (21/125)

cos(θ + φ) = -96/125 - 21/125

cos(θ + φ) = -117/125

8 0
2 years ago
Write an equation in slope-intercept form for the line with slope -2/5 and y-intercept 6 .
lana66690 [7]

y=(-2/5)x + 6

Step-by-step explanation:

y-6= (-2/5)x or y=(-2/5)x + 6

5 0
2 years ago
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