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Scrat [10]
2 years ago
5

Sherri solved the equatjon 1/5(x-20)=45. For each step, write the name of the property sherri used

Mathematics
1 answer:
adoni [48]2 years ago
7 0

Answer: The awnser is linear.

I hope this helped.

Step-by-step explanation:

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ivolga24 [154]

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3 years ago
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Find the solution set of the inequality
Brilliant_brown [7]

<u>Answer:</u>

\boxed{\textsf{ Hence the solution set is$ \bf{\bigg( \dfrac{33}{4},\infty \bigg) }$}}.

<u>Step-by-step explanation:</u>

A inequality is given to us and we need to find the solution set. So the given inequality to us is ,

  • -4x + 35 >2

\bf\implies -4x + 35 > 2 \\\\\bf\implies -4x > 2-35 \\\\\bf \implies -4x > -33 \\\\\bf \implies x >\dfrac{-33}{-4}\\\\\bf \implies x > \dfrac{33}{4} \\\\\bf\implies \boxed{\pink{\bf x \in \bigg(\dfrac{33}{4}, \infty \bigg) }}

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>solution</u><u> </u><u>set </u><u>is </u><u>x </u><u>€</u><u> </u><u>(</u><u> </u><u>3</u><u>3</u><u>/</u><u>4</u><u> </u><u>,</u><u> </u><u>∞</u><u> </u><u>)</u><u>.</u></h3>
3 0
3 years ago
If 8 identical blackboards are to be divided among 4 schools, how many divisions are possible? how many if each school must rece
DaniilM [7]
Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then 

( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165

For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
8 0
3 years ago
2x-1+3x=0 5x-1=0 how can we get equation b from a
cluponka [151]
2x - 1 + 3x = 0
2x + 3x - 1 = 0
(2 + 3)x - 1 = 0
5x - 1 = 0
7 0
3 years ago
A = {1, 3, 5, 7, 9}
lutik1710 [3]

The upside down U means the numbers the sets have in common.

Do what is in parenthesis first:

(B ∩ C) = 6 is the only common number in set B and Set C.

A ∩ (B ∩ C) = Would be all the numbers in A plus the number 6 from (B ∩ C).

The answer would be A) {1, 3, 5, 6, 7, 9}

8 0
3 years ago
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