Answer:
279...................................
<u>Answer:</u>

<u>Step-by-step explanation:</u>
A inequality is given to us and we need to find the solution set. So the given inequality to us is ,
<h3>
<u>★</u><u> </u><u>Hence </u><u>the </u><u>solution</u><u> </u><u>set </u><u>is </u><u>x </u><u>€</u><u> </u><u>(</u><u> </u><u>3</u><u>3</u><u>/</u><u>4</u><u> </u><u>,</u><u> </u><u>∞</u><u> </u><u>)</u><u>.</u></h3>
Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then
( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165
For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
2x - 1 + 3x = 0
2x + 3x - 1 = 0
(2 + 3)x - 1 = 0
5x - 1 = 0
The upside down U means the numbers the sets have in common.
Do what is in parenthesis first:
(B ∩ C) = 6 is the only common number in set B and Set C.
A ∩ (B ∩ C) = Would be all the numbers in A plus the number 6 from (B ∩ C).
The answer would be A) {1, 3, 5, 6, 7, 9}