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3 years ago

Use the details of Osborn's new credit card to answer the question that follows.

Mathematics

2 answers:

Fittoniya [83]3 years ago

4 0

530(1+.144/12)(.06) = 32.18 so even that is less than 35
So the answer is 31.80

nexus9112 [7]3 years ago

3 0

My answer is 31.80. hope this helps.

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if it takes anne 1/2 hour to read 2/3 of a chapter. About how long will it take her to read a chapter?

kolbaska11 [484]

Answer:

45 minutes

Step-by-step explanation:

1/2 hour=30 minutes

2/3 of chapter=30 minutes

1/4 of hour=15 minutes

1/3 of chapter=15 minutes

3/4 of hour=45 minutes

3/3 of chapter=45 minutes

6 0

2 years ago

Please help is due at 8:00 pm

tester [92]

Answer:

Answer is C

Step-by-step explanation:

Please mark brainliest if I helped!

3 0

3 years ago

Name the vertical angles in the diagram below:

SVETLANKA909090 [29]

Hey there!

The vertical angles in the diagram shown are 2 and 3, and 1 and 4, because they are formed by 2 intersecting lines and are across from eachother.

Hope it helps and have a good day!

7 0

2 years ago

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

2 years ago

Plisss help on my assesment

Anon25 [30]

Answer:

The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is NOT equivalent [the 7x+21 ≠ 2(5x+3)]

Step-by-step explanation:

Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.

1. 6x+48 and 2(3x+24)

2(3x+24) ---> 2(3x) + 2(24) ---> 6x + 48

Bring in the first expression ~ 6x+48 and 6x+48

They are the same, so they are equivalent

2. 7x+21 and 2(5x+3)

2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6

Bring in the first expression ~ 7x+21 and 10x + 6

They are NOT the same, so they are NOT equivalent

6 0

2 years ago