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Reil [10]
2 years ago
9

Perimeters and Areas of Rectangles (PLEASE HELP)

Mathematics
2 answers:
Lynna [10]2 years ago
6 0

Answer:

i will only answer 11 and 4

Step-by-step explanation:

4: 23 i know its not the whole thing

11:45 its not the full thing

Yuliya22 [10]2 years ago
6 0

Answer:

You need to take lw (what l equals times what w equals) the area and then take 2l+2l=perimiter

Step-by-step explanation:

Example: 4. area: 12x2=24 the area is 24 units squared. For the perimeter, you need to take 12+12+2+2= 24+4=28 The perimeter is 28 units.

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Matt reasoned that he can write 9/1,000 as 0.9. Is he correct? Explain your answer.
GuDViN [60]
No because 9/1,000 in decimals would be 0.009 because if the number was a 3 number then it would go in the tenths
5 0
3 years ago
When you identify the author of a text, which of the following are you are specifically examining in the source?
ioda
I would say origin, but it's a hard choice.
3 0
3 years ago
Read 2 more answers
Solve -1/2w-3/5=1/5w
elena55 [62]
Very easy:

Common denominator:
-5/10w - 3/5 = 2/10w

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-30 = 35w

-30/35 = w

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That's how you do it mate ;)
8 0
3 years ago
Workout to the simplest:<br><img src="https://tex.z-dn.net/?f=%20%20%5Cint%20%5C%3A%20%20%7Bx%7D%5E%7B2%7D%20%20ln%28%20%7Bx%7D%
Roman55 [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
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Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.
Georgia [21]
Correct Ans:
Option A. 0.0100

Solution:
We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.

First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

z-score= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10} } } \\  \\ &#10;z-score =2.326

So, 90 converted to  z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.

Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
5 0
3 years ago
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