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s344n2d4d5 [400]
3 years ago
8

What is 2/3(6e+9f-21g)

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0
 I think the answer is -7f
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Find the absolute maximum and minimum values of the following functions on the given curves functions:
bagirrra123 [75]

Answer:

Solution has explained below:

Step-by-step explanation:

(a) f(x,y) = x+y

To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx= 1, fx₁=0 and

fy= 1 and fyy=0

For stationary points fx=fy=0, which gives,

1=1=0, so that there is just one stationary point, (x,y)=(0,0)

If  fx₁  < 0 and fyy < 0, function is maximum

If  fx₁ > 0 and fyy > 0, function is minimum.

(b) g(x,y) = xy

Sol: To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx= 1 and fy  = 1

fx₁ = 0 and fyy =0

for stationary points fx = fy =0, which gives 1=1=0, so that there is just one stationary points, (x,y) =(0,0)

If fx₁ < 0 and fyy < 0, function is maximum.

If  fx₁  > 0 and fyy> 0, function is minimum.

c) h(x,y) = 2x2 + y2

sol: To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx = 4x  and fy = 2y

fx₁= 4  and fyy = 2

Now, taking fx = 0 and fy = 0

Gives x=0 and y=0,

Stationary points are (x,y) = (0,0)

If fx₁ < 0 and fyy < 0, solution is maximum,

If fx₁ > 0 and fyy > 0, solution is minimum,

Here, fx₁ = 4 > 0 and fyy = 2 > 0.

6 0
3 years ago
A miniature quadcopter is located at xi = −1.75 m and yi = −5.70 m at t = 0 and moves with an average velocity having components
Black_prince [1.1K]

The quadcopter's average velocity is given in terms of change in position by

\vec v_{\rm av}=\dfrac{\Delta x}{\Delta t}\,\vec\imath+\dfrac{\Delta y}{\Delta t}\,\vec\jmath

where \Delta x=x_f-x_i, the difference in the quadcopter's final and initial positions and \Delta t=(1.60-0)\,\mathrm s=1.60\,\mathrm s.

The x-component of the average velocity is 2.70 m/s, so

2.70\dfrac{\rm m}{\rm s}=\dfrac{x_f-(-1.75\,\mathrm m)}{1.60\,\rm s}\implies \boxed{x_f=2.57\,\mathrm m}

and the y-component is -2.50 m/s, so

-2.50\dfrac{\rm m}{\rm s}=\dfrac{y_f-(-5.70\,\mathrm m)}{1.60\,\rm s}\implies\boxed{y_f=-9.70\,\mathrm m}

4 0
3 years ago
Which of the following is the mathematical representation of Boyle's law?
Ratling [72]
The mathematical representation of Boyle's law is P1V1 = P2V2. The answer to your question is C. I hope that this is the answer that you were looking for and it has helped you.
3 0
3 years ago
1.  Lisa is working with the system of equations x + 2y = 7 and 2x ‒ 5y = 5. She multiplies the first equation by 2 and then sub
Musya8 [376]
All methods are supposed to be correct in most if not all situations and it should not matter if you use a different method given the options
3 0
3 years ago
Read 2 more answers
Given f(x)=8x+13 and g(x)=x^2-5x, find (f-g)x
uysha [10]

(f-g)x= -x²+13x+13

Hope it helps you....

4 0
3 years ago
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