Answer: Joe's weekly allowance = $12
Step-by-step explanation:
Joe spent half of his weekly allowance playing mini-golf
Let a = his weekly allowance
This means Joe spent a/2 playing mini-golf.
To earn money, his parents let him weed the garden for $6
This means Joe's total money
= a + 6
What is his weekly allowance if he ended with $12?
This means he had $12 left after spending a/2 from ta total of (a +6)
Therefore,
(a +6) -a/2 = 12
Taking LCM of 2
[2(a+6)-a]/2=12
Cross multiplying by 2
2a + 12-a = 24
a+12 =24
a = 24-12 =$12
Joe's weekly allowance = $12
Answer:
im pretty sure its 30%. because 70% are in heath. so 30% of the students arent. i think... hope this helped.
Step-by-step explanation:
Answer:
AE=22.4
Step-by-step explanation:
BE is 1/2 of BC
BC is 20 cm All sides of a square are equal
BE = 1/2 BC Property of a midpoint.
BE = 10
Now just use Pythagorus
AB^2 + BE^2 = AE^2
AE^2 = 20^2 + 10^2 Perform the sqrs
AE^2 = 400 + 100 Add the terms
AE^2 = 500 Take the square root of both sides
√AE^2 = √500
AE = 22.36
AE ≈ 22.4
Answer:
Step-by-step explanation:
<u>The missing reasons are:</u>
- 1. k. Given
- 2. j. Definition of parallelogram
- 3. d. Definition of linear pair
- 4. b. Linear pair postulate
- 5. e/m. Definition of supplementary
- 6. g. Same side interior angles theorem
- 7. e/m. Definition of supplementary
- 8. a/c. Substitution property of congruence
- 9. i. Subtraction property of congruence
- 10. f. Alternate interior angles theorem
- 11. l. Alternate exterior angles theorem
- 12. h. Angle congruence postulate
Answer:
a. a[1] = 3; a[n] = 2a[n-1]
b. a[n] = 3·2^(n-1)
c. a[15] = 49,152
Step-by-step explanation:
Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.
The first term is 3, and the common ratio is 2.
<h3>(a)</h3>
The recursive rule is ...
a[1] = 3
a[n] = 2×a[n-1]
__
<h3>(b)</h3>
The explicit rule is ...
a[n] = a[1]×r^(n-1)
a[n] = 3×2^(n-1)
__
<h3>(c)</h3>
The 15th term is ...
a[15] = 3×2^(15-1) = 3×2^14
a[15] = 49,152
