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Sphinxa [80]
3 years ago
5

Subtract (-2) + 3 – 6. Hint: Add the first two numbers, then subtract the 6 from the result of that addition.

Mathematics
1 answer:
mina [271]3 years ago
7 0

The answer is -5.

Step-by-step explanation:

The answer is -5 because -2 plus 3 equals 1 and 1 minus 6 equals -5

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huong and kathyrn each day impeoved their yards by planting rose bushes and ornamental grass. they bought their supplies from th
marta [7]

Answer:

One rose bush = $3

One bunch of ornamental grass = $4

Step-by-step explanation:

We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

14r+7g=70\\5r+14g=71

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

(*-2)14r+7g=70\\5r+14g=71\\-------\\-28r-14g=-140\\5r+14g=71\\--------\\-23r=-69\\r=\frac{-69}{-23}=3

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

14r+7g=70\\14(3)+7g=70\\42+7g=70\\7g=70-42\\7g=28\\g=\frac{28}{7}=4

Thus, 1 bunch of ornamental grass is $4.

5 0
3 years ago
For which value of Theta is tan Theta equal to sin Theta?<br>A. pi<br>B. pi/2<br>C. pi/4<br>D. pi/6​
AnnyKZ [126]

Answer:

a. pi

Step-by-step explanation:

7 0
3 years ago
Carl ran around the track 3 more times than Daria and 2 fewer times than Erin. When they were done they added up the number of l
Paul [167]

Answer:

Total laps = 10d

Step-by-step explanation:

Let c = Carl's laps

d = Daria's laps

e = Erin's laps

c = 3d

c = e/2

c + d + e = totals laps

We can insert 3d in place of c in the third equation

3d + d + e = total laps

Also, e/2 equals 3d

e/2 = 3d

Multiply both sides by 2

(e/2 = 3d)2

e = 6d

Insert the new e

3d + d + 6d = 10d = totals laps

3 0
3 years ago
How do we find the factors of x2 – 64
sweet-ann [11.9K]

Answer:

The factors of x²-64 is equal to (x-8)(x+8).

Step-by-step explanation:

The given expression is:

x²-64

we know that, 8² = 64

So,

(x²-8²) = (x-8)(x+8) [As (a-b)(a+b) = a²-b²]

So, the factors of x²-64 i equal to (x-8)(x+8).

8 0
3 years ago
Simplify the expression using properties of exponents. -16a-3b-5 2a-4b2
lions [1.4K]

a^n\cdot a^m=a^{n+m}\\\\-16a^{-3}b^{-5}\cdot2a^{-4}b^2=(-16\cdot2)(a^{-3}a^{-4})(b^{-5}b^2})\\\\=-32a^{-3+(-4)}b^{-5+2}=\boxed{-32a^{-7}b^{-3}}

8 0
3 years ago
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