H + 5.4 = −5.4 pls help if you know

Mathematics

2 answers:

ss7ja [257]2 years ago

3 0

Answer:

$\sf H = -10.8$

________

$\sf Solve$

$\sf Move~terms~not~containing~H~to~the~right.$

$-5.4 + 5.4 = -10.8$

________

now, note that if this was actually subtracting, logically, the answer would be H = 0

however, this is an addition problem, meaning to add a negative and a positive integer to get a negative integer.

Natalka [10]2 years ago

3 0

Multiply 5.4 x2 and put a negative symbol in front

You might be interested in

Nguyen was climbing a cliff. He stopped for a snack. After that, he

Yuki888 [10]

He traveled 20 feet after his snack

8 0

3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$