Answer:
The interquartile range is the difference between the highest and lowest values in the middle of a data set.
Step-by-step explanation:
The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.
The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.
The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.
Answer:
Teo is 11 years old and Richard is 26 years old.
Step-by-step explanation:
Let R be the age of Richard and T be the age of Teo.
<u><em>First set up the equations:</em></u>
The combined age of Teo and Richard is 37:
R+T=37
Richard is four years old than twice Teo's age:
R=2T+4
<u><em>Then, solve the equations:</em></u>
Substitute (2) to (1) and solve for T:
(2T+4)+T=37
3T=11
T=11
Solve for R using (2):
R=2(11)+4
R=22+4
R=26
Answer: D
Step-by-step explanation:
1. Subtract 36 to 28.80
2. Divide the answer to the first price (36.00)- 7.5 divided by 36.00 or 36
3. When you calculate and find the answer as a decimal, then make it into a percentage
So if... you divide 7.5 divided by 36, you get the decimal of 0.2, and when you move the decimals two places only, you get your answer of 20%.
Hopefully it helped you!. Have a good day :-).
<u>Answer:</u>
The correct answer option is P (S∩LC) = 0.16.
<u>Step-by-step explanation:</u>
It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.
So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.552 = P(S∩LC) / 0.29
P (S∩LC) = 0.552 × 0.29 = 0.16
The domain- Is the function provides an "output" or value for each member of the domain
Range- The difference between the lowest and highest values.
