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Ad libitum [116K]
2 years ago
5

Find the value of each variable in the parallelogram.

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
7 0

Answer:

a=79, b=101

Step-by-step explanation:

the consecutive angles are supplementary angles, and the opposite ones are congruent.

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3 years ago
You can walk 3 miles per hour, jog 5 miles per hour, or run 10 miles per hour. You go a full hour before changing pace. At the e
Studentka2010 [4]

Answer:

b. How many ways arc there to go 12 miles?

≡ p(12) = 25

c. How many ways arc there to go 20 miles?

≡ p(20) = 131

d. How many ways arc there to go 22 miles?

≡p(22)  199

Step-by-step explanation:

a) supposed you walked for the first hour. Then you would have travelled 3 miles. if you jogged you would have covered 5miles and if you run you would have covered 10miles. now you have to decide how to run the rest miles from the n miles.

Thus, the number of ways one can cover n miles will be given by the recurrence relation

p(n) = p( n-3) + p( n-5) + p( n - 10)

now to solve the rest of the question, let us make a table which provides the number of ways for n = 1  to 22.

check the attachment for the table

b. How many ways arc there to go 12 miles?

≡ p(12) = 25

c. How many ways arc there to go 20 miles?

≡ p(20) = 131

d. How many ways arc there to go 22 miles?

≡p(22)  199

8 0
3 years ago
How to solve -2 2/5 subtract 7/10 <br> How to solve -3 subtract 1/10
galben [10]

Answer: 11

Step-by-step explanation:

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(275 ÷ 100) × 4 =

(275 × 4) ÷ 100 =

1,100 ÷ 100 = 11

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4 years ago
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Whats the square root of 39 to the nearest whole
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The square root of 39 is 6.224
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3 years ago
Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.0 ounces and a standard deviation of 1.1 ounces.

This means that \mu = 8, \sigma = 1.1

(a) If 5 potatoes are randomly selected, find the probability that the mean weight is less than 9.3 ounces?

n = 5 means that s = \frac{1.1}{\sqrt{5}} = 0.4919

This probability is the pvalue of Z when X = 9.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{9.3 - 8}{0.4919}

Z = 2.64

Z = 2.64 has a pvalue of 0.9959

0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.0 ounces?

n = 6 means that s = \frac{1.1}{\sqrt{6}} = 0.4491

This probability is 1 subtracted by the pvalue of Z when X = 9. So

Z = \frac{X - \mu}{s}

Z = \frac{9 - 8}{0.4491}

Z = 2.23

Z = 2.23 has a pvalue of 0.9871

1 - 0.9871 = 0.0129

0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

8 0
3 years ago
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