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2 years ago

Please help me GENIUS Rank

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

4 0

<h2>Hey there!</h2>

<h3>Here's your required mode </h3>

<h3>Refer to the image above </h3>

<h3>And btw,in the earlier question I've done for mean also you can check that again which I've answered earlier. </h3>

<h2>Hope it helps</h2>

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Can someone help ASAP?<br>

Olin [163]

Answer

$6\sqrt{13}/13$

Step-by-step explanation:

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3 years ago

What would a monthly payment be on a purchase of a $10,000 car at a 5.9% for 4 years?

gizmo_the_mogwai [7]

The current monthly pay can be calculated as follows;
A=p(1/r/100)^n
A=10000
r=5.9/12=0.5%
10000=p(1+0.5/100)^(4*12)
10000=p(1.005)^48
p=10000/(1.005)^48
p=7,871
the monthly payment will be:
7871/12
=$655.92

5 0

3 years ago

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Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

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In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

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3 years ago

Mr. Freye distributed $126 equally among his 4 children for their weekly allowance how much money did each child receive?

mote1985 [20]

Answer:

$10.50

Step-by-step explanation:

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2 years ago

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What is the answer to this equation? <br><br> 4x+39

RSB [31]

Answer:

U CAN'T SOLVED IT BECAUSE IT HAS A VARIABLE AND A NUMBER U CANNOT COMBINED THEM

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3 years ago

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