Option one because it’s going up by 50 and it’s also showing that she’s starting with the 200$ she already had
Answer:
98 ft²
Step-by-step explanation:
There are a couple of ways you can think about this one. Perhaps easiest is to treat it as a square with a triangle cut out of it. The cutout triangle has a base (across the top) of 14 ft and a height of 14 ft, so its area is ...
A = (1/2)(14 ft)(14 ft) = 98 ft²
Of course the area of the square from which it is cut is ...
A = (14 ft)² = 196 ft²
So, the net area of the two triangles shown is ...
A = (196 ft²) - (98 ft²) = 98 ft²
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Another way to work this problem is to attack it directly. Let the base of the left triangle be x. Then the base of the right triangle is 14-x, and their total area is ...
A = A1 + A2 = (1/2)(x ft)(14 ft) + (1/2)((14-x) ft)(14 ft)
We can factor out 7 ft to get ...
A = (7 ft)(x ft + (14 -x) ft)
A = (7 ft)(14 ft) = 98 ft²
X² - 6x - 9 = 0
x² - 3x - 3x - 9 = 0
x (x-3) -3(x + 3) = 0
(x - 3)² = 0
In short, Your Answer would be Option A
Hope this helps!
Answer:
The answer would be D: d || f.
Step-by-step explanation:
- Since the angles 4 and 7 are parallel, it would make sense for the lines that the angles are on to be parallel as well.
- It just so happens that line d and line f are completely parallel to each other and angles 4 and 7 are on the lines. So the answer would be D.
Answer:
No graph so we'll use the quadratic formula
x^2+x-4=0
a = 1
b = 1
c = -4
x = -1 +- sqr root (1^2 - 4 * 1 * -4) / 2
x = (-1 +- sqr root (1 +16) ) / 2
x1 = (-1 + sqr root (17)) / 2
x2 = (-1 - sqr root (17)) / 2
Step-by-step explanation:
