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Marat540 [252]
2 years ago
15

Janice wears uniform number 6 .Lily's uniform number is 4 times as great as Janice's. Addison's uniform number is 20 more than J

anice's uniform number.
Mathematics
2 answers:
marta [7]2 years ago
5 0
.... The answer is the first sentence of the question? XD 6.
Paul [167]2 years ago
5 0
Lily=24 Addison=120 Lily=6
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HURRY !! which comparison of the two equations is accurate? (picture)
VladimirAG [237]

Answer:

its c .Both equations have the same potential solutions, but equation A might have extraneous solutions.

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
I need help and NOW PLEASE
mixas84 [53]

Answer:

a) 7/4 b) 15/2

Step-by-step explanation:

a) Scale Factor = Image / Object

Take the side of Triangle ABC that's BC Why? Because it corresponds with the Image Triangle ADE's DE

= 21/12 = 7/4

b) 7/4 = 10+ x / 10

Cross Multiply

= 4 ( 10 + x ) = 70

= 40 + 4x = 70

= 4x = 70-40

= 4x = 30

= 4x/4 = 30/4

x = 15/2

3 0
3 years ago
A bakery sold 119 chocolate cupcakes in a day, which was 35% of the total number of cupcakes sold that day. How many total cupca
Mashcka [7]

Answer: <em>Bakery sold 340 cupcakes</em>

Step-by-step explanation:

<em>119 ÷ 35% × 100% = 340</em>

4 0
3 years ago
At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05. A bucket of 3 pieces of dark meat
Alenkinab [10]

Answer:

The cost of a piece of dark meat is <u>$0.70</u> and the cost of a piece of white meat is <u>$0.85</u>.

Step-by-step explanation:

Given:

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05.

A bucket of 3 pieces of dark meat and 8 pieces of white meat costs 8.90.

Now, to find the cost of a piece of dark meat and the cost of a piece of white meat.

Let the cost of a piece of dark meat be x.

And the cost of a piece of white meat be y.

A bucket of 4 pieces of dark meat and 5 pieces of white meat costs $7.05.

So,

4x+5y=7.05

4x=7.05-5y  

x=\frac{7.05-5y}{4}   .......(1)

Now, a bucket of 3 pieces of dark meat and 8 pieces of white meat costs $8.90.

3x+8y=8.90

Substituting the value of x from equation (1) we get:

3(\frac{7.05-5y}{4})+8y=8.90

\frac{21.15-15y}{4} +8y=8.90

\frac{21.15-15y+32y}{4} =8.90

<em>Multiplying both sides by 4 we get:</em>

21.15-15y+32y=35.60

21.15+17y=35.60

<em>Subtracting both sides by 21.15 we get:</em>

17y=14.45

<em>Dividing both sides by 17 we get:</em>

y=0.85

<u>The cost of a piece of white meat = $0.85.</u>

Now, substituting the value of y in equation (1) we get:

x=\frac{7.05-5y}{4}

x=\frac{7.05-5\times 0.85}{4}

x=\frac{7.05-4.25}{4}

x=\frac{2.8}{4}

x=0.70.

<u>The cost of a piece of dark meat = $0.70.</u>

Therefore, the cost of a piece of dark meat is <u>$0.70</u> and the cost of a piece of white meat is <u>$0.85</u>.

5 0
2 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean µ, of 1850 pounds, and a standard deviation of 9
saul85 [17]

Answer:

We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased

Step-by-step explanation:

Normal Distribution

Population Mean   μ₀  = 1850 pounds

Standard Deviation   σ  =  90 pounds

Type of test

Null Hypothesis                         H₀     ⇒    μ  =  μ₀

Alternative Hypothesis            Hₐ      ⇒    μ > μ₀

A one tail test  (right)

n = 21  as    n  < 30  we use t-student table

degree of fredom   20  

t = 2.845

Sample mean   μ = 1893

Then, we compute t statistics

t(s)  =  [ 1893 - 1850 ] / 90/ √n

t(s)  =   43 * 4,583 / 90

t(s)  = 197,069 / 90

t(s)  =  2,190

And we compare t  and  t(s)

t(s)  =  2.190

t =  2.845

Then  t(s)  <  t

We are in the acceptance zone, we accept  H₀

5 0
2 years ago
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