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Marat540 [252]
3 years ago
15

Janice wears uniform number 6 .Lily's uniform number is 4 times as great as Janice's. Addison's uniform number is 20 more than J

anice's uniform number.
Mathematics
2 answers:
marta [7]3 years ago
5 0
.... The answer is the first sentence of the question? XD 6.
Paul [167]3 years ago
5 0
Lily=24 Addison=120 Lily=6
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SOLVE FOR ANGLE P PLEASE FOR BRAINLIEST :) NO EXPLANATION NO BRAINLIEST
hoa [83]

Answer:

50 degrees

Step-by-step explanation:

In triangles, the sum of all angles = 180 degrees. So, we can create an equation to solve for x:

  • Angle 1 + Angle 2 + Angle 3 = 180 degrees
  • (x+15) + (x+28) + 67 = 180
  • 2x + 110 = 180
  • 2x = 70
  • x = 35

We found x, but we're not done. Now, we substitute to find each missing angle:

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Thus, our final answer is: Angle P = 50 degrees.

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3 years ago
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How can I tell if a system of equations has one, no, or infinitely many solutions?
Fittoniya [83]

Answer:

There are many ways to interpret if whether or not a system of equations has solutions or not. Here is one way that is most ideal for most, if not, all equations: using graphs.

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3 years ago
Suppose m is in the line given by the equation 6x-3y=7, and suppose n is the line perpendicular to m and passing Nd through the
stealth61 [152]

Answer:

The x co-ordinate o intersection of line k and n is \frac{8}{11}

Step-by-step explanation:

Given as :

The equation of line m is 6 x - 3 y = 7

So, in the standard form , line equation is

y = a x + c  , where a is the slope

So,  6 x - 3 y = 7 can be written as

3 y = 6 x - 7

or,  y = 2 x - \frac{7}{3}       ........1

So, slope of this line = a = 2

Now, The line n is perpendicular to line m and passing through line ( 6 , 2 )

So, Slope of line n = b

For , perpendicular lines , products of slope = - 1

Or, a × b = -1

∴  b = - \frac{1}{a}

I.e b = - \frac{1}{2}

So,equation of line n with slope b and passing through line ( 6 , 2 ) is

y - y_1 = b ( x - x_1 )

or, y - 2 =  - \frac{1}{2} ( x - 6 )

or, 2 × ( y - 2 ) =  - 1 ( x - 6 )

or, 2 y - 4 = - x + 6

or, x + 2 y -10 = 0          ........2

Again, equation of line k with slope 5 and y intercept = 1

For y intercept , x coordinate = 0

y = c x + c

or, 1 = c× ( 0 ) + c

Or, c = 1

Or, equation of line k is

y = 5 x + 1           ..........3

Now intersection of line k and n is

put the value of y from eq 3 into eq 2

I.e x + 2 × (  5 x + 1  )-10 = 0  

Or, x + 10 x + 2 - 10 = 0

or, 11 x - 8 = 0

or 11 x = 8

∴  x = \frac{8}{11}

Hence The x co-ordinate o intersection of line k and n is \frac{8}{11}  Answer

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27 + 5 x 6 A Little Problem With this so some help please?
Kay [80]

Answer:

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2) Then <em>add</em>: 27+30=57

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Step-by-step explanation:

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