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stira [4]
2 years ago
10

I need help with this one please

Mathematics
2 answers:
Tpy6a [65]2 years ago
8 0
\bold{ANSWER:}
x = 110/12

\bold{SOLUTION:}

Mamont248 [21]2 years ago
4 0
Answer- x=9.16 x signifies how much more money the student needs to add to the $20 to reach 350 in 12 months.

Explanation- divide both sides by 12, then subtract 20.
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A restaurant manager can spend at most $400 a day for operating costs and payroll. It costs $100 each day to operate the bank an
horrorfan [7]

Answer:

The restaurant Manager can afford 6 employees for the day.

Step-by-step explanation:

Manager can spend at most of $400.

Total Money ≤ $400

Cost to operate bank = $100

Cost for each employee = $50

Let number of employees for the day bex

Hence the equation will become;

50x + 100 \leq 400

Solving this equation we get;

50x + 100 \leq 400\\50x \leq 400-100\\50x \leq 300\\x\leq \frac{300}{50}\\\\x\leq 6

Hence, The restaurant Manager can afford 6 employees for the day.

3 0
4 years ago
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What is the solution to the system of equations shown in the graph?
kotykmax [81]
What graph? We can’t solve if we don’t have a graph.
7 0
3 years ago
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Fractions from 6 to 7, with an interval of between each pair of fractions
EastWind [94]

Answer:

6.7

Step-by-step explanation:

3 0
3 years ago
Plz answer :( I need this done by tonight!!!
damaskus [11]

Answer:

40

Step-by-step explanation:

The entire line is 180°

since 140° is occupied, there is a 40° angle.

I hope isn't too late :'(

7 0
3 years ago
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Verify csc^4x-cot^4x=2csc^2x-1
Oksanka [162]
First, factor the left side:

(csc^2(x))^2-(cot^2(x))^2

This can be simplified using x^2-y^2 = (x+y)(x-y) where the csc term is x and the cot term is y:

(csc^2(x)+cot^2(x))(csc^2(x)-cot^2(x))

One of our Pythagorean Identities states that:

csc^2(x)-cot^2(x)=1

So the left side is now:

csc^2(x)+cot^2(x)

Now we can use the same Pythagorean Identity to change the right side to:

2csc^2(x)-(csc^2(x)-cot^2(x))

All we did was express 1 in terms of csc and cot.

Distribute the negative:

2csc^2(x)-csc^2(x)+cot^2(x)

Combine like terms:

csc^2(x)+cot^2(x)

Now the left and right sides are the same.
8 0
3 years ago
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