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Archy [21]
2 years ago
14

5x + 6y = 16 -10x-12y = 25

Mathematics
1 answer:
Doss [256]2 years ago
6 0

Answer:

  no solution

Step-by-step explanation:

There is no solution to this inconsistent system of linear equations. They describe parallel lines.

__

Adding twice the first equation to the second gives ...

  2(5x +6y) +(-10x -12y) = 2(16) +(25)

  0 = 57 . . . . . . . simplify. False

No values of x and y will make this statement true. There is NO SOLUTION to the system of equations.

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Answer:

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Step-by-step explanation:

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3 years ago
Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

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\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

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2 years ago
Another question I'm stuck on
qwelly [4]
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Ivan

Answer:

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Step-by-step explanation:

sin 48 = opposite/ hypotenuse

sin 48 = 10/x

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