3 years ago

5x + 6y = 16 -10x-12y = 25

Mathematics

1 answer:

Doss [256]3 years ago

6 0

Answer:

no solution

Step-by-step explanation:

There is no solution to this inconsistent system of linear equations. They describe parallel lines.

Adding twice the first equation to the second gives ...

2(5x +6y) +(-10x -12y) = 2(16) +(25)

0 = 57 . . . . . . . simplify. False

No values of x and y will make this statement true. There is NO SOLUTION to the system of equations.

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Which is the value of this expression when a = 5 and k = negative 2? (3^2 a^-3)(3 a^-4)^-2

lozanna [386]

Answer:

$5^5=3125$

Step-by-step explanation:

$Given\ (3^2a^{-3})(3a^{-4})^{-2}\\\\=3^2a^{-3}\cdot(3)^{-2}(a^{-4})^{-2}\\\\=3^2\times3^{-2}\times a^{-3}\times a^8\ \ \ \ \ \ (x^{-m})^{-n}=x^{mn}\\\\=3^{2-2}\times a^{-3+8}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x^m\times x^n=x^{m+n}\\\\=3^0\times a^5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x^0=1\\\\=1\times a^5\\\\=a^5\\\\put\ value\ a=5\\\\=5^5\\\\=3125$