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koban [17]
1 year ago
11

Solve for the unknown length.

Mathematics
1 answer:
tatyana61 [14]1 year ago
8 0
<h2>Similar Triangles</h2>

Similar triangles have the same proportions of sides, but they have different side lengths.

To solve for missing sides in similar triangles, we can set up a proportion.

For instance, let's say that side <em>a</em> in Triangle A corresponds with side <em>b</em> in Triangle B. Let's say that side <em>h</em> in Triangle A also corresponds with side <em>k</em> in Triangle B. Then, it would be true that:

  • \dfrac{a}{b}=\dfrac{h}{k}

We need to make sure of a couple things:

  • The numerators and denominators of fractions are corresponding
  • The numerators describe one triangle, and the denominators describe another (can't switch, otherwise the calculations will get messed up)

<h2>Solving the Question</h2>

We're given two triangles (do you see it?).

  • Triangle ABC
  • Triangle ADE

These two triangles are similar.

We must solve for the length of side BC in Triangle ABC.

  • We're given the length of DE, the corresponding side in Triangle ADE.
  • We're also given the lengths of bottom sides, 20 units and 30 + 20 = 50 units.

Set up a proportion:

\dfrac{x}{15}=\dfrac{50}{20}\\\\\dfrac{x}{15}=\dfrac{5}{2}\\\\x=\dfrac{5}{2}*15\\\\x=\dfrac{75}{2}\\\\x=37.5

Therefore, the unknown length is 37.5 units.

<h2>Answer</h2>

37.5 units

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How many grams make a kilogram?

In each kilograms, there are 1,000 grams, which means we need to first of all convert the total number of apples in kilograms to grams.

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36 crates=900 kilograms

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The number of grams left after having sold 486,235 grams of apples, in essence, the quantity of apples left thereafter is 900,000 grams minus the 486,235 grams of apples sold

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Given: KLMN is a trapezoid, m∠N=m∠KML, FD=8, LM KN = 3 5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 5 Find: KM
denis23 [38]

Answer:

The length of side KM is \sqrt{109} units.

Step-by-step explanation:

Given information:  KLMN is a trapezoid, ∠N= ∠KML, FD=8, LM:KN=3:5, F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3\sqrt{5}.

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is 3\sqrt{5}.

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since LM:KN=3:5, therefore LM is 3x and KN is 5x.

\frac{3x+5x}{2}=8

\frac{8x}{2}=8

x=2

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

KN=KA+AE+EN

10=6+2(EN)                (KA=EN, isosceles trapezoid)

EN=2

KE=KN-EN=10-2=8

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

Hypotenuse^2=base^2+perpendicular^2

(KM)^2=(KE)^2+(ME)^2

(KM)^2=(8)^2+(3\sqrt{5})^2

KM^2=64+9(5)

KM=\sqrt{109}

Therefore the length of side KM is \sqrt{109} units.

8 0
3 years ago
Read 2 more answers
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