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lozanna [386]
2 years ago
10

A quantity with an initial value of 620 grows continuously at a rate of 0.3% per second. What is the value of the quantity after

0.5 minutes, to the nearest hundredth?
Mathematics
1 answer:
denis23 [38]2 years ago
6 0

Answer:

678.39

Step-by-step explanation:

For this we should probably use the formula A = Pe^rt. The question says that the value grow "continuously" which is our hint that we should use A = Pe^rt rather than A = P(1 +r/n)^nt. Our P = 620 as it is our initial value. e is a constant approx = 2.718. r is our rate, so 0.3% = 0.003, and our t will be in seconds. We need to figure out how many seconds are in .5 minutes, so 30, and that means our t will = 30. Let's plug these in. 620e^(0.003 * 30) = A. This will give us our answer which when rounded to the hundredths = 678.39.

Hope this is helpful.

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strojnjashka [21]

The general term of an arithmetic sequence is,

a_{n} =a_{1} +(n-1)d

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Here a_{1}= 57,

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Next step is to plug in these values in the above formula. Therefore,

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