All categories

3 years ago

A store discounted an item by 25% and then an additional 40%. The item was sold for $18.00 what is the original price ?

Mathematics

1 answer:

Ksivusya [100]3 years ago

7 0

Answer: 33

Step-by-step explanation:

You might be interested in

Solve for x <br><br> 3(x+2)+4(x-5)=10

Natasha_Volkova [10]

Answer:

x=24/7

Step-by-step explanation:

3(x+2)+4(x-5)=10

3x+6+4(x-5)=10

3x+6+4x-20=10

7x+6-20=10

7x-14=20

7x=24

x=24/7

8 0

2 years ago

Draw a model to represent 42/7

ch4aika [34]

Here is a model I have made (I'm not a great artist). There are 42 circles in total, placed in 7 columns. Each column has 6 circles. This model represents 42/7 by splitting 42 into 7 parts, which are the columns, and showing that each column has 6 circles, which is the answer to 42/7.

7 0

2 years ago

Write y=(x-7)(x-1) in standard form

Oxana [17]

In order to write this quadratic equation in standard form, first note that standard form is ax^2+bx+c for quadratics, where c is the numerical value (constant), B is the coefficient of x, and a is the coefficient of x^2 and is the leading coefficient. Next, multiply the binomials of (x-7) and (x-1). You can do this by using FOIL, or by distributing each of the terms in a binomial to each of the other terms in the other binomial. (Please let me know if you need a walk through in this step in particular). Furthermore, you should then write y= (the simplified trinomial). Now, the quadratic is in standard form. To reiterate, just simplify the two binomials by multiplying them together and writing that they're equal to y.

5 0

3 years ago

PLZ HELP ME

Likurg_2 [28]

Answer:

x ≈ 14.87

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² = 10² + 11² = 100 + 121 = 221 ( take the square root of both sides )

x = $\sqrt{221}$ ≈ 14.87 ( to the nearest hundredth )

8 0

2 years ago

Find the measure of ∠ 2.<br><br> degrees

miv72 [106K]

$If\ it's\ a\ rhombus,\ then\ |\angle1|=26^o\\\\|\angle1|+|\angle2|+26^o=180^o\ \ /it's\ a\ triangle/\\\\26^o+|\angle2|+26^o=180^o\\52^o+|\angle2|=180^o\ \ \ |subtract\ 52^o\ from\ both\ sides\\\boxed{|\angle2|=128^o}$

7 0

3 years ago