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3 years ago

Carlos gave Lucy 2 more books than she already had. She now has 30 books. How many books did Carlos give Lucy?

Mathematics

1 answer:

ankoles [38]3 years ago

3 0

Answer:

2 books

Step-by-step explanation:

"Carlos gave Lucy 2 more books than she already had"

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The graph is of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?

Reika [66]

The real solutions of f(x) = 0 is; x = -8, 0 and 4

<h3>How to find the roots of a polynomial graph?</h3>

When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.

Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.

From the given graph, the real solutions are at x = -8, 0 and 4

Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4

Read more about Polynomial roots graph at; brainly.com/question/14625910

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2 years ago

What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22

sdas [7]

<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120

Median = 90
Lower Median = 73
Upper Median = 101

IQR = 101 - 73
IQR = 28</span>

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4 years ago

Ejercicio 34 - College Board

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3 years ago

How many grams of NH3 are required to produce 4.65 g of HF

nignag [31]

1.326 grams of NH3 are required to produce 4.65 g of HF.

Step-by-step explanation:

Balanced chemical reaction is written first to know the number of moles taking part in original reaction.

NH3 +3 F2 ⇒3 HF + NF3

Given:

mass of HF = 4.65

First the number of moles of HF in 4.65 grams is calculated by using the formula:

number of moles (n) = $\frac{mass}{atomic mass of 1 mole}$

atomic mass of HF = 20 grams/mole

putting the values in the above equation number of moles can be found.

n = $\frac{4.65}{20}$

= 0.235 moles of HF are given.

From the equation it can be said that:

1 mole of NH3 reacts to form 3 moles of HF

so, x moles of NH3 would react to form 0.235 moles of HF

$\frac{3}{1}$ = $\frac{0.235}{x}$

3x = 0.235

x = $\frac{0.235}{3}$

x = 0.078 moles of NH3 is required.

The moles are converted to mass by applying the formula:

mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)

putting the values in the formula

mass = 17 X 0.078

mass = 1.326 grams

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3 years ago